anonymous
  • anonymous
1. Determine the equation of the line, in standard form, that will get your spacecraft from the Launch Area to Point A Launch Area: (1, 2) Point A: (0, -1)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@PFEH.1999
anonymous
  • anonymous
|dw:1378482467421:dw|
anonymous
  • anonymous
that's the two points on the graph, yeah?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
yes...
anonymous
  • anonymous
and use this formula:
anonymous
  • anonymous
okay, I have that drawn on a graph paper for this assigment
anonymous
  • anonymous
\[\frac{ y-y _{1} }{ x-x _{1} } = \frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }\]
anonymous
  • anonymous
that's what I don't get, I don't understand what y and x would be
anonymous
  • anonymous
ok , I'll show you :)
anonymous
  • anonymous
Okay! :D
anonymous
  • anonymous
\[y _{1} = 2 \ , \ y _{2}=-1 \ , \ x _{1} = 1 \ , \ x _{2} = 0\]
anonymous
  • anonymous
and y and x will be equation of the line..
anonymous
  • anonymous
ok?
anonymous
  • anonymous
okay, let me write it out on my paper
anonymous
  • anonymous
negative 3 over negative 1?
anonymous
  • anonymous
wait...you should write in this way: y = (N)x not negative 3 over negative 1?
anonymous
  • anonymous
\[y = \frac{ -3 }{ -1}\]
anonymous
  • anonymous
and x=?
anonymous
  • anonymous
let me write it...
anonymous
  • anonymous
okay
anonymous
  • anonymous
no it is: y=3x-1
anonymous
  • anonymous
ok?
anonymous
  • anonymous
okay
anonymous
  • anonymous
you found it:y = 3x-1
anonymous
  • anonymous
any problem?
anonymous
  • anonymous
so the equation of the line is y=3x-1?
anonymous
  • anonymous
yes :)
anonymous
  • anonymous
Okay, so I would explain my work like this \[\frac{ y2-y1 }{ x2-x1}\] \[\frac{ -1-2 }{ 0-1}\] y=3x-1
anonymous
  • anonymous
yes...you're quite correct...
anonymous
  • anonymous
okay, thank you!
anonymous
  • anonymous
your welcome:)

Looking for something else?

Not the answer you are looking for? Search for more explanations.