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LaynaMae

  • 2 years ago

Help please ?

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  1. LaynaMae
    • 2 years ago
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  2. LaynaMae
    • 2 years ago
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    @ganeshie8 I only have 4 more questions ! D:

  3. ganeshie8
    • 2 years ago
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    good :)

  4. LaynaMae
    • 2 years ago
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    Yay so you're willing to help ? :)

  5. ganeshie8
    • 2 years ago
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    yes why not for a brilliant student like u, its easy to explain :)

  6. LaynaMae
    • 2 years ago
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    Great ! Thank you so so much ! You have no idea how much I appreciate it :)

  7. ganeshie8
    • 2 years ago
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    ok, so Juliana has $24 in her pocket. and she wants to knw how many text messages she can send

  8. LaynaMae
    • 2 years ago
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    Right

  9. ganeshie8
    • 2 years ago
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    she knows that \(f(x) = (3x+2)/4 \) gives the cost, when u put number of messages x into the equation

  10. ganeshie8
    • 2 years ago
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    for example, if u have texted 10 messages cost wud be :- f(10 ) = (3(10)+2)/4 = 32/4 = 8 so it wil cost u $8 just to text 10 msgs... pretty costly !!

  11. LaynaMae
    • 2 years ago
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    Okay makes sense !

  12. ganeshie8
    • 2 years ago
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    but thats not wat we want, here our task is to find a function, into which we can plugin the MONEY we have, and it should tell us how many TEXTS we can message

  13. LaynaMae
    • 2 years ago
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    I tried working it out and got 18.5 ..

  14. ganeshie8
    • 2 years ago
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    right ?

  15. LaynaMae
    • 2 years ago
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    I think I'm getting ahead of myself here haha i apologize

  16. LaynaMae
    • 2 years ago
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    And yes , right :)

  17. ganeshie8
    • 2 years ago
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    its okay, but 18.5 messages for $24 doesnt look correct

  18. ganeshie8
    • 2 years ago
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    let me show u how to do this step by step

  19. LaynaMae
    • 2 years ago
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    Please and thank you !

  20. ganeshie8
    • 2 years ago
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    given equaiton :- \(y = f(x) = (3x+2)/4 \) here, x is number of texts, y is dollars

  21. ganeshie8
    • 2 years ago
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    since you wanto know how many texts u can send, you need to solve x above.

  22. ganeshie8
    • 2 years ago
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    \(y = (3x+2)/4\) solve x

  23. LaynaMae
    • 2 years ago
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    How would I start off ?

  24. ganeshie8
    • 2 years ago
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    multiply 4 both sides

  25. LaynaMae
    • 2 years ago
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    4(3x+2) ?

  26. ganeshie8
    • 2 years ago
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    \(y = (3x+2)/4\) multiply 4 both sides \(4y = 3x+2\)

  27. ganeshie8
    • 2 years ago
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    next, subtract 2 both sides

  28. ganeshie8
    • 2 years ago
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    \(y=(3x+2)/4 \) multiply 4 both sides \(4y=3x+2\) subtract 2 both sides \(4y-2 = 3x\) divide 3 both sides \(\large \frac{4y-2}{3} = x\)

  29. ganeshie8
    • 2 years ago
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    now, replace x and y (just do it, il tell you later why :))

  30. ganeshie8
    • 2 years ago
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    replace x & y \(\large \frac{4x-2}{3} = y \) \(\large y = \frac{4x-2}{3} \)

  31. LaynaMae
    • 2 years ago
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    Isn't it to put the equation in the correct form ?

  32. ganeshie8
    • 2 years ago
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    thats the required function, where u need to plugin x=$24, and it gives u number of text messages u can send !

  33. ganeshie8
    • 2 years ago
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    exactly ! you're right, we replace x and y, to put the function in right form :)

  34. LaynaMae
    • 2 years ago
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    Yay :D

  35. ganeshie8
    • 2 years ago
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    put x = 24, and see how many messages she can send

  36. LaynaMae
    • 2 years ago
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    Wait so that's the answer ?

  37. ganeshie8
    • 2 years ago
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    yes thats the required function ! since the question wants u to explain, explain wat we did so far :)

  38. ganeshie8
    • 2 years ago
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    btw, for $24, she can send :- \(\large y = \frac{4x-2}{3}\) \(\large y = \frac{4(24)-2}{3}\) \(=33\)

  39. ganeshie8
    • 2 years ago
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    sorry, that should be 31, so she can send 31 messages

  40. LaynaMae
    • 2 years ago
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    So with $24 she can send 33 text messages ?

  41. ganeshie8
    • 2 years ago
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    *31

  42. LaynaMae
    • 2 years ago
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    Oh okay :) So everything we just worked through is the answer basically ? Because it says to put in complete sentences

  43. ganeshie8
    • 2 years ago
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    yes ! ima hav dinner... brb :)

  44. LaynaMae
    • 2 years ago
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    Haha okay !

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