Help me with graphing please? :/

- LifeIsADangerousGame

Help me with graphing please? :/

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- anonymous

Post the graph :)

- LifeIsADangerousGame

I need to find the solution
\[y \le - 1/2x - 8\]
\[y \ge -1/2\]

- LifeIsADangerousGame

augh\[y \ge -1/2x + 5\] is what the second should be

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## More answers

- anonymous

What are you trying to get? The first graph is going to be Full line over -15x and -8Y
Im doing the second one now :D

- anonymous

The second one is going to be Posotive 5 going up and positive 10 on the right side incase your not sure about the Y and X's yet :)

- anonymous

Shaded in on both with line NOT dotted I repeat NOT dotted full lines on both inequalitys :)

- anonymous

*Inequality's

- LifeIsADangerousGame

I need to "Give one point in the solution area or state no solution." as my answer

- anonymous

Can you copy and paste the question "word for word"?

- anonymous

first: graphe both inequalities like regular lines
\[y= (-1/2)x - 8\] and \[y= (-1/2)x + 5\] both inequalities will be solid lines. you need to determine where the shaded region is going to be by plugging in some numbers. when you get your result, you need to ask yourself is this <= or >=. where ever the result is true, shade that entire region. do this for both inequalities. the intersection is the solution.

- anonymous

Your looking for the intersection of them?

- LifeIsADangerousGame

##### 1 Attachment

- LifeIsADangerousGame

ignore the file name xD

- jdoe0001

I guess now we know what you're having for lunch :P

- anonymous

lol. What are the possible answers?

- LifeIsADangerousGame

XD nice jdoe, and there are no possible answers, I have to come up with the answer

- anonymous

It's a word problem?

- LifeIsADangerousGame

not really? I have to graph the two equations then tell her what teh solution to them is

- jdoe0001

hmmm, is rather simple, since it's already solved for "y", or in so-called slope-intercept form anyhow, so graph both lines first, that is \(\bf y = \color{blue}{-\cfrac{1}{2}}x-8 \qquad y = \color{blue}{-\cfrac{1}{2}}x+5\)
btw, notice the slopes for both graphs

- LifeIsADangerousGame

The slope for both graphs is -1/2 I'll try to draw a graph|dw:1378495346865:dw| is that right?

- anonymous

Yes! IT IS! :D

- anonymous

Is your teacher asking you what type of lines these are? If so. They are Parallel lines lol

- LifeIsADangerousGame

xD Thanks Blakarican, Jdoe, if its right does that mean there's no solution?

- jdoe0001

yes, now test POINTS NOT IN THE LINEs, for the shading
say let's test in between for both, let's say the point .... in between of (0, 2)
\(\bf y \le -\cfrac{1}{2}x-8 \implies 2 \le -\cfrac{1}{2}0-8 \implies 2 \le-8\)
now, is 2 really less or equal to -8? no, thus is false, thus the middle region is false for that line, if that's false, that means the OTHER SIDE OF IT, is the TRUE part, so the shading is above it

- LifeIsADangerousGame

other side of which line?

- jdoe0001

I tested it the -8 one so that'd be |dw:1378496273643:dw|

- LifeIsADangerousGame

So now to answer my teacher's question, I pick a point in the shaded area correct? so say, (-5,-7)?

- anonymous

There is a slope but im not sure if they ever will cross because they are parallel. Both of them are shaded in. On the side where the line is opposing. Their shades or not touching just like the parallel line :)

- jdoe0001

so lemme test the same mddle-region point for the 2nd inequality, see what we get
(0, 2)
\(\bf y \ge -\cfrac{1}{2}x+5 \implies 2 \ge -\cfrac{1}{2}0+5 \implies 2 \ge 5\)
now is 2 really greater than or even equal to 5? no, thus is also false, for the 2nd inequality

- jdoe0001

so one shades DOWN, the other shades UP
do their shading ever meet, even though they're parallel lines, well, no, thus no common shaded area, no solution

- anonymous

Yep They don't meet ^-^

- LifeIsADangerousGame

Ohh, wow that's a lot less complicated than it seems

- LifeIsADangerousGame

Thanks jdoe and Blakarican c:

- jdoe0001

yw

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