LifeIsADangerousGame
  • LifeIsADangerousGame
Help me with graphing please? :/
Linear Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Post the graph :)
LifeIsADangerousGame
  • LifeIsADangerousGame
I need to find the solution \[y \le - 1/2x - 8\] \[y \ge -1/2\]
LifeIsADangerousGame
  • LifeIsADangerousGame
augh\[y \ge -1/2x + 5\] is what the second should be

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anonymous
  • anonymous
What are you trying to get? The first graph is going to be Full line over -15x and -8Y Im doing the second one now :D
anonymous
  • anonymous
The second one is going to be Posotive 5 going up and positive 10 on the right side incase your not sure about the Y and X's yet :)
anonymous
  • anonymous
Shaded in on both with line NOT dotted I repeat NOT dotted full lines on both inequalitys :)
anonymous
  • anonymous
*Inequality's
LifeIsADangerousGame
  • LifeIsADangerousGame
I need to "Give one point in the solution area or state no solution." as my answer
anonymous
  • anonymous
Can you copy and paste the question "word for word"?
anonymous
  • anonymous
first: graphe both inequalities like regular lines \[y= (-1/2)x - 8\] and \[y= (-1/2)x + 5\] both inequalities will be solid lines. you need to determine where the shaded region is going to be by plugging in some numbers. when you get your result, you need to ask yourself is this <= or >=. where ever the result is true, shade that entire region. do this for both inequalities. the intersection is the solution.
anonymous
  • anonymous
Your looking for the intersection of them?
LifeIsADangerousGame
  • LifeIsADangerousGame
1 Attachment
LifeIsADangerousGame
  • LifeIsADangerousGame
ignore the file name xD
jdoe0001
  • jdoe0001
I guess now we know what you're having for lunch :P
anonymous
  • anonymous
lol. What are the possible answers?
LifeIsADangerousGame
  • LifeIsADangerousGame
XD nice jdoe, and there are no possible answers, I have to come up with the answer
anonymous
  • anonymous
It's a word problem?
LifeIsADangerousGame
  • LifeIsADangerousGame
not really? I have to graph the two equations then tell her what teh solution to them is
jdoe0001
  • jdoe0001
hmmm, is rather simple, since it's already solved for "y", or in so-called slope-intercept form anyhow, so graph both lines first, that is \(\bf y = \color{blue}{-\cfrac{1}{2}}x-8 \qquad y = \color{blue}{-\cfrac{1}{2}}x+5\) btw, notice the slopes for both graphs
LifeIsADangerousGame
  • LifeIsADangerousGame
The slope for both graphs is -1/2 I'll try to draw a graph|dw:1378495346865:dw| is that right?
anonymous
  • anonymous
Yes! IT IS! :D
anonymous
  • anonymous
Is your teacher asking you what type of lines these are? If so. They are Parallel lines lol
LifeIsADangerousGame
  • LifeIsADangerousGame
xD Thanks Blakarican, Jdoe, if its right does that mean there's no solution?
jdoe0001
  • jdoe0001
yes, now test POINTS NOT IN THE LINEs, for the shading say let's test in between for both, let's say the point .... in between of (0, 2) \(\bf y \le -\cfrac{1}{2}x-8 \implies 2 \le -\cfrac{1}{2}0-8 \implies 2 \le-8\) now, is 2 really less or equal to -8? no, thus is false, thus the middle region is false for that line, if that's false, that means the OTHER SIDE OF IT, is the TRUE part, so the shading is above it
LifeIsADangerousGame
  • LifeIsADangerousGame
other side of which line?
jdoe0001
  • jdoe0001
I tested it the -8 one so that'd be |dw:1378496273643:dw|
LifeIsADangerousGame
  • LifeIsADangerousGame
So now to answer my teacher's question, I pick a point in the shaded area correct? so say, (-5,-7)?
anonymous
  • anonymous
There is a slope but im not sure if they ever will cross because they are parallel. Both of them are shaded in. On the side where the line is opposing. Their shades or not touching just like the parallel line :)
jdoe0001
  • jdoe0001
so lemme test the same mddle-region point for the 2nd inequality, see what we get (0, 2) \(\bf y \ge -\cfrac{1}{2}x+5 \implies 2 \ge -\cfrac{1}{2}0+5 \implies 2 \ge 5\) now is 2 really greater than or even equal to 5? no, thus is also false, for the 2nd inequality
jdoe0001
  • jdoe0001
so one shades DOWN, the other shades UP do their shading ever meet, even though they're parallel lines, well, no, thus no common shaded area, no solution
anonymous
  • anonymous
Yep They don't meet ^-^
LifeIsADangerousGame
  • LifeIsADangerousGame
Ohh, wow that's a lot less complicated than it seems
LifeIsADangerousGame
  • LifeIsADangerousGame
Thanks jdoe and Blakarican c:
jdoe0001
  • jdoe0001
yw

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