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is the answer 19y^2 - 3 or 19y -9 ?
Which do you think? :)
those are both the answers I came up with... i just solved the problem two different ways hahaha I'm not sure which way is the right way to solve it
OK, well.... one of the ways you did it is right and one is wrong. :) Here is the right way: –3(–4y + 3) + 7y distribute = 12y - 9 + 7y put like terms together = 12y + 7y -9 add like terms = 19y - 9 You can't get a y^2 term from there, because there is NOWHERE that you are multiplying that y by another factor of y. And I have no idea where the -3 would come from either.... so whatever you did to get THAT answer is wrong. If you want to show me what you did, I can walk you through where your error is.
I distributed the -3 at the beginning
ok, that's correct - you should get 12y - 9 + 7y and then?
Ohhhhhh I see what I did! I forgot to distribute the -3 to the positive 3 lol
OK, that still doesn't explain how you had a -3 instead of 3 (I guess you distributed the "-" but not the 3? lol) or how you got the y^2... you can't get y^2 from y, unless you multiply by another y. :) But as long as you see what you did wrong and won't do it next time, that's all that matters!! :)
Oh, I think you added 12y + 7y and made it 19y^2? but you see why that doesn't work now, right? :) When you add like terms, you JUST add together the coefficients!
Haha yes thats exactly what I did.. thank you :)
you're welcome. :)