anonymous
  • anonymous
If you save three pennies on January 1, six pennies on January 2, nine pennies on January 3, and continue this pattern for one year (not a leap year), what will be the value of your entire savings, in dollars, at the end of that one year? Express your answer as a decimal.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
its just increasing by 3 pennies each day
anonymous
  • anonymous
so on jan 4th you will have 12 pennies and so on
anonymous
  • anonymous
ok can you please explain and show how [:

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anonymous
  • anonymous
how many pennies do you think he will have on jan 5th?
anonymous
  • anonymous
and do you have choices for answers?
Loser66
  • Loser66
let n is the order of the day, \(a_n\) is the money you save on that day n=1 \(a_1=3\) n =2 \(a_2= 6 = a_1*2\) n = 3 \(a_3 =9 = a_1*3\) n = 4 \(a_4 = 12 = a_1 *4\) ----and----so----on------------- so, if n = 365 \(a_{365}= a_1* 365\) therefore, \(a_1 +a_2+a_3+.....+a_{365} \) is the total money you can save for the whole year And you have formula \(\sum_ {n=1}^{365} 3n\) and how to calculate this sum? You google to know, I explain you the way how to construct that formula. That's it.

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