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even i belive
you just look at the expontes
it is online hw and i only have one attempt to get it right
u have to be 100% sure
\[f(x)=x \left| x^2 \right|\]
is it odd, even or neither
So in theory, IF: \(f(x)=f(-x)\) THEN It is even. \(-f(x)=f(-x)\) THEN it is odd.
So if we know that \(f(x)=x|x^2|\), Lets check to see if the identities are correct! Try computing f(-x) and -f(x) and see what those return and if it fits any of the above equations.
can u give me an answer?
i get confused with the absolute value
I don't get what hes saying what my teacher told me is you just look at the exponets
Oh yeah...good point. Try this: \[f(x)=x|x^2|\] \[f(-x)=(-x)|(-x)^2|=-x|x^2|\] \[-f(x)=-(x)|x^2|=-x|x^2|\] So since \(f(-x)=-f(x)\) The function is odd.
I am \(200\%\) sure that \(f(x)=x|x^2|\) is odd
what do i do if it gives me two graphs
If what does...?
it gives me http://roy.math.umn.edu/webwork2_course_files/umtymp-calculus1-f13/tmp/gif/muzzammil-Q-raza-524-setReview_and_Rate_of_Changeprob4image1.png
don't know if the link works
good luck t(-_-)t
i wil do it on my own i just want u to help me start
And what you want to do with the graph?
find out if they r odd, even or neither
Visually you can identify a function as odd even or neither by imagining this: If the right or left side of \(f(x)\) can be rotated about the y-axis to match the other side, it is even. If the If the right or left side of \(f(x)\) can be rotated about the line of \(y=x\) or \(y=-x\) to match the other side, it is odd. Otherwise it is neither.
so what do u think
lol why don't you think instead of just asking for answers
i think its red=even and blue=odd. what do u think
Well think about it, could you flip one side of the red over the y axis to match the other?
have u looked at the graph
Yes muzzamil, I have.
buddy i really need help on this
LOL KEITH WALK AWAY NOW
Have you? Take a look. Imagine you grab one side and fold it over the y-axis. Does it fit on the other side?
i said i think red is even and blue is odd. atlesat i am trying
i asked if u thouht i was right
Well why do you think that?
and he is asking you a question and you haven't answered it and if you did it answers your question llol
kramer instead of wasting ur precious time maybe u should leave. i did what u told me to
trust me my time at the moment is not precious
i keep asking ur opinion cuz my a$$ is on the line. my parents get pissed if i mess up on my hw. its an asian thing
didn't you get taught the lesson in school?
i also want to watch football this weekend and i need this done. i am a ninth grader taking calculus at the university of minnesota. the professors suck there
bro that isn't calculus that's pre calc
its th first chapter of the book
u dont do derivatives the first day
x is odd. x^2 is even abs(x^2) is redundant because x^2 is always positive. Therefore, f(x) = x^3 and it is definitely odd.
we already solved that. we r on the graph one. i posted a link @tkhunny
I would have to agree that it is not calculus but it may be review of pre calc in the beginning. How youre accepted in Minnesota University at grade 9 is beyond me.
because hes a liar lol
UMTYMP. university of minnesota talented youth math program
look it up. mathcep.umn.edu
I saw the solution. I just wanted to make sure we used the word "redundant".
@tkhunny this guy just wants answers no work don't waste your time
@llkramer did u look it up?
\[f(x)=x|x|^2\] \[f(2)=2\times |2|^2=\] \[f(-2)=-2\times |-2|^2=-8\]
we already solved this @satellite73 . we r now on the link i posted with the two graphs
DONT GIVE HIM A ANSWER BRO
what a pretty picture what are you supposed to do with it?
r the graphs even, odd, or neither
i think red=even and blue=odd
the one that is symmetric with respect to the \(y\) axis is even the one that is symmetric with respect to the origin \((0,0)\) is odd
yes, you are right
LOL @satellite73 "What a pretty picture" haha that got a good laugh a out of me.
THANK YOU @satellite73 FINALLY SOMEBODY WHO COULD ACTUALLY TELL ME IF I WAS RIGHT OR WRONG.
@satellite73 That's EXACTLY what I thought when It was first shown to me
THEN Y COULDN''T U SAY THAT
U COULD HAVE SAVED US LIKE 30 MIN
Though math is about right and wrong, It is even more about the WHY. "yes" and "no" wont get you very far without the WHY.
WELL THANKS FOR THE FIRST ONE ANYWAY
Is this some sort of an "ALL CAPS RAGE" or so?
Bye. GOOD LUCK