anonymous
  • anonymous
Bill steps off a 3.0-m-high diving board and drops to the water below. at the same time, ted jumps upward with a speed of 4.2 m/s from 1.0-m-high diving board
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Choosing the origin to be 3.0 m {\rm m} above the water, and downward to be the positive x x direction, write x x-versus-t t equations of motion for both Bill and Ted.
anonymous
  • anonymous
This is what I have so far as the answer xbill= -0.5gt^2+3.0 because the intial velocity is zero xted=-0.5gt^2+4.3+1. But i'm not sure
Shane_B
  • Shane_B
Let me clean that up a bit: First note that given the coordinate system the problem gives you, g will be positive and the origin is at the same point as the high diving board. Therefore, Bill's equation should be pretty clear since he's starting at 0 velocity: \[\Large x_{Bill}=\cancel{(0m/s)t}+\frac{1}{2}gt^2\] Ted is starting at 1m above the water which is 2 meters below the origin. \[\Large x_{Ted}=2m=(-4.2m/s)t+\frac{1}{2}gt^2\]Now you can just simplify Ted's equation a bit and you're done.

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anonymous
  • anonymous
Thank you so much :)
Shane_B
  • Shane_B
No problem, good luck!

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