anonymous
  • anonymous
HELP!!!! Center at the origin, Transverse axis at x-axis, distance between foci is 2√97, latus rectum is 32/9
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
HELP PLEASE!!!
tkhunny
  • tkhunny
So, it's an ellipse. Center at the Origin gives: \(\dfrac{x^2}{a^{2}} + \dfrac{y^{2}}{b^{2}} = 1\) x-Axis is Transverse (or Major) Axis give: a > b Distance between foci gives \(c = \sqrt{97}\) Latus Rectum is 32/9 gives \(2\cdot\dfrac{b^{2}}{a} = 32/9\) Well, that's all the problem statement gave us. Now what?
anonymous
  • anonymous
its hyperbola.. hehe wait, 2√97, what happened to 2?

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tkhunny
  • tkhunny
Well, you shoudl have said so! c is HALF the distance between the foci. Just like a is half the length fo the Transverse Axis and b is half the length of the congugate axis.
anonymous
  • anonymous
sorry.. thank you :)
tkhunny
  • tkhunny
Change it to -y^2 instead of +y^2, and we're still on the right track.
anonymous
  • anonymous
why is it changed to negative?
tkhunny
  • tkhunny
Because it an hyperbola and not an ellipse.
anonymous
  • anonymous
yes yes.
anonymous
  • anonymous
ahm, how to get a and b?

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