anonymous
  • anonymous
a physics book is moved once around the perimeter of a table of dimensions 1 m by 3m. if the book ends up at its intial position what is the magnitude of its displacement
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Shane_B
  • Shane_B
First, welcome to OpenStudy!! If any object ends up in the same place in which it started, it's displacement must be 0. Remember that there's a big difference between displacement and distance. The book traveled through a distance equal to the perimeter of the table...but since it's back where it started, it's displacement was 0.
anonymous
  • anonymous
Thank you so much!
Shane_B
  • Shane_B
No problem :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
what would be the distance traveled?
Shane_B
  • Shane_B
What do you calculate the perimeter of the table to be? That's your answer :)
anonymous
  • anonymous
:) do you know how many questions i can ask?
Shane_B
  • Shane_B
As many as you like!
Shane_B
  • Shane_B
The distance you should get is 8m
anonymous
  • anonymous
oh my god! thanks! are you willing to help me with like 29 questions or less if i can get the hang of it?
Shane_B
  • Shane_B
If not me I'm sure someone will. Just post each one separately and give medals to those that help you :)
anonymous
  • anonymous
how do you give medals? this is my first time joining
Shane_B
  • Shane_B
Click the "Best Response" button...that's it
anonymous
  • anonymous
oh ok.. so are you a paid tutor? how does this work?
Shane_B
  • Shane_B
This site is completely free. 99% of the people here are no paid and just like helping others.
Shane_B
  • Shane_B
are *not* paid...typo
anonymous
  • anonymous
wow that is so nice! so i have more questions, is that alright?
Shane_B
  • Shane_B
Yes, just post them as new questions. One main question per thread
anonymous
  • anonymous
okay, what is bump?
Shane_B
  • Shane_B
I believe that bumps your question to the top...my screen doesn't show it but I don't ask questions...just try to help others
anonymous
  • anonymous
that is so nice :)
Shane_B
  • Shane_B
Helping folks keeps me from forgetting all this stuff...so I get something out of it too :)
anonymous
  • anonymous
if the average speed of an orbiting space shuttle is 19400 mi/h, find the time required for it to circle earth. consider the fact that the shuttle is orbiting about 204.6 mi above earths surface, and assume that earths radius is 3963 mi. answer in of h
Shane_B
  • Shane_B
Post it as a NEW question :) Look up to the left of your screen and paste that into the "Ask a question" box
Shane_B
  • Shane_B
More people will see it that way :)
anonymous
  • anonymous
okay thanks so much for your time shane
Shane_B
  • Shane_B
My pleasure
Shane_B
  • Shane_B
For this last question just think of circles. 1) Add the height above earth to the radius to get the total radius of the orbit 2) Calculate the perimeter of the orbit based on this new radius (Circumference = 2 pi R). 3) Divide the speed by the circumference to get the time it takes it takes to circle the earth once
anonymous
  • anonymous
thanks that helps a lot

Looking for something else?

Not the answer you are looking for? Search for more explanations.