anonymous
  • anonymous
Find the value of Q in the following system so that the solution to the system is: {(x,y) : x-3y = 4} x-3y=4 Qx-6y=8
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Q=2
anonymous
  • anonymous
how did you get that answer? @ask1709
anonymous
  • anonymous
ok i looked at it and i saw that since its a system, the equations are the same. so, if you look at the equations, u see that the second equation is just the same as the first on but it is expressed 2 times larger

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More answers

anonymous
  • anonymous
-3y*2=-6y
anonymous
  • anonymous
4*2=8
anonymous
  • anonymous
so the answer would be Q=8?
anonymous
  • anonymous
no it would be 2
anonymous
  • anonymous
since 1*2=?
anonymous
  • anonymous
sorry i'm not a good explainer
anonymous
  • anonymous
its okay! are you still in 7th grade? @ask1709
anonymous
  • anonymous
no now i just got in 8 but I now do geometry(10th grade math)
anonymous
  • anonymous
oh wow you're good! Im doing pre-cal :p
anonymous
  • anonymous
thanks @ali1029 but how come you are asking algebra 1 questions?
anonymous
  • anonymous
youre welcome. & lol im in pre-cal but it just started and i guess we're reviewing algebra 1 &2 but i suck at math so i dont know anything lol @ask1709
anonymous
  • anonymous
So you are 11th grade?
anonymous
  • anonymous
Well I am in geometry but I can do basic pre cal. thats why I enjoy this website because i like solving math.
anonymous
  • anonymous
thats awesome for you! i wish math was my good subject :( im better in english and all that. lol emberassing but im a senior this year @ask1709
anonymous
  • anonymous
thanks @ali1029 but I tutor a junior and he is just like you he is really good at literature, but is confused about math
anonymous
  • anonymous
yes that is definitely me all the way haha, well congrats to you! you're amazing for your age!
anonymous
  • anonymous
thanks
anonymous
  • anonymous
But you are definitely a better explainer than me!
anonymous
  • anonymous
haha no worries! i can only explain the super easy stuff, anything more advanced- forget it! :p @ask1709

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