anonymous
  • anonymous
Factor expression: 2X^(3/2)+6X^(1/2)-4X^(-1/2)
Precalculus
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[2x ^{\frac{ 3 }{ 2 }} + 6x ^{\frac{ 1 }{ 2 }} - 4x ^{\frac{ -1 }{ 2 }}\]
anonymous
  • anonymous
?
anonymous
  • anonymous
yes!

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More answers

anonymous
  • anonymous
2x3=6 2x2=4 2x1=2 ok?
anonymous
  • anonymous
yup
anonymous
  • anonymous
so the factor is: \[2x ^{\frac{ 1 }{ 2 }}(1+3-2^{-1})\]
anonymous
  • anonymous
wait , in the bracket, isn't it (x+3-....)
anonymous
  • anonymous
because we factor out x^1/2 from X^3/2
anonymous
  • anonymous
wait I think I made mistake...
anonymous
  • anonymous
It will be:
anonymous
  • anonymous
\[2x ^{\frac{ 1 }{ 2 }}(x ^{3}+3-2^{-1})\]
anonymous
  • anonymous
ok?got it?
anonymous
  • anonymous
why is it X^3?
anonymous
  • anonymous
3/2 - 1/2 = 1
anonymous
  • anonymous
shouldn't it be just x
anonymous
  • anonymous
x^1 = x
anonymous
  • anonymous
you are quite right sorry,sorry,sorry...so please write it.
anonymous
  • anonymous
but i dont know about the last one ...
anonymous
  • anonymous
1+1/2 = 3/2
anonymous
  • anonymous
4x^(-1/2) factor out 2x^1/2, leaves what?
anonymous
  • anonymous
you are right ;)
anonymous
  • anonymous
leaves 2^-1?
anonymous
  • anonymous
wait 'm confused :D let me doing it...
anonymous
  • anonymous
or 2X^-1
anonymous
  • anonymous
its ok
anonymous
  • anonymous
ok i think it's like......\[2x ^{1/2} (x+3-\frac{ 2 }{ x })\]
anonymous
  • anonymous
because 2/x = \[2X ^{-1}\]
anonymous
  • anonymous
well i'm guessing......
anonymous
  • anonymous
true :)
anonymous
  • anonymous
ok cool

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