anonymous
  • anonymous
Find the angle between the given vectors to the nearest tenth of a degree. u = <-5, -4>, v = <-4, -3>
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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ganeshie8
  • ganeshie8
use dot product u.v = ||u|| ||v|| cos\(\theta\)
ganeshie8
  • ganeshie8
<-5, -4> . <-4, -3> = ||<-5, -4> || ||<-4, -3> || cos \(\theta\) solve \(\theta\)
anonymous
  • anonymous
I keep getting 5 squareroot 41

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ganeshie8
  • ganeshie8
yes i also got 5 squareroot41 :) <-5, -4> . <-4, -3> = ||<-5, -4> || ||<-4, -3> || cos \(\theta\) 20+12 = \(\sqrt{41} \times 5\) cos \(\theta\) 32 = \(5\sqrt{41} \) cos \(\theta\)
ganeshie8
  • ganeshie8
you still need to solve \(\theta\)
ganeshie8
  • ganeshie8
\(\large \frac{32}{5\sqrt{41}} = \cos \theta\)
ganeshie8
  • ganeshie8
use ur calculator and find \(\theta\)
ganeshie8
  • ganeshie8
\(0.999512 = \cos \theta\) \(\cos \theta = 0.999512 \) can u find \(\theta\) ?
anonymous
  • anonymous
Wait, 0.9 is the answer, if I am not mistaken.
ganeshie8
  • ganeshie8
nopes
ganeshie8
  • ganeshie8
when u have, \(\cos \theta = 0.999512\) you must take cos inverse both sides, to isolate \(\theta\)
ganeshie8
  • ganeshie8
\(\cos \theta = 0.999512\) \(\cos^{-1}\cos \theta = \cos^{-1}0.999512\) \( \theta = \cos^{-1}0.999512\)
ganeshie8
  • ganeshie8
do you knw how to take \(\cos^{-1} 0.999512\) in your calcualtor ? :)
ganeshie8
  • ganeshie8
you may use wolframalpha :- http://www.wolframalpha.com/input/?i=arccos%280.99951207%29
anonymous
  • anonymous
1.79 = 1.8.
ganeshie8
  • ganeshie8
perfect !
anonymous
  • anonymous
Once again, Thank you, very much.
ganeshie8
  • ganeshie8
you're wlcme :)

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