anonymous
  • anonymous
HELP MY FRIEND!!!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
what do you need help on?
anonymous
  • anonymous
|dw:1378562854375:dw|
anonymous
  • anonymous
so you are trying to find g(x)?

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anonymous
  • anonymous
Trying to find g(f(x))
anonymous
  • anonymous
oh..... did you try to set them equal to each other?
anonymous
  • anonymous
your not trying to find them by themselves, you are trying to find f(x) within g(x)
anonymous
  • anonymous
you should ask @DebbieG for help they might be able to help you
anonymous
  • anonymous
sorry i couldn't help you much :(
DebbieG
  • DebbieG
So you want g(f(x)), given that \(\Large f(x)=x^2-3\\ \Large g(x)=x^2+1\) Remember what function notation means: it means that you "plug in" whatever is in the ( ) for the variable in the definition of the function, right? E.g. if \(\Large g(x)=x^2+1\\ \text{then } \Large g(6)=6^2+1\\ \text{and } \Large g(a)=a^2+1\\ \text{and } \Large g(r+1)=(r+1)^2+1\\\) Right? So to find \(\Large g(f(x))\) you'll just want to plop \(f(x)\) into \(g(x)\) in place of the variable x, and simplify the resulting expression: \(\Large g(f(x))=g(x^2-3)=(x^2-3)^2+1\) Expand that product and add like terms.

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