anonymous
  • anonymous
Theorem: A line parallel to one side of a triangle divides the other two proportionately. In the figure below, segment DE is parallel to segment BC and segment EF is parallel to AB. The figure shows triangle ABC with segments DE and EF. Point D is on side AB, point E is on side AC and point F is on side BC. Segment AD is 6, segment AE is 12, segment EC is 18, and segment FC is 24 Which statement can be proved true using the given theorem? Segment BD = 12 Segment BD = 4 Segment BF = 16 Segment BF = 9
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
anonymous
  • anonymous
@ganeshie8 how do i set up the proprtions?
ganeshie8
  • ganeshie8
look at options, they involve two lengths : BD and BF

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ganeshie8
  • ganeshie8
so, lets find them both
anonymous
  • anonymous
okay
ganeshie8
  • ganeshie8
yes we need to setup proportions :)
anonymous
  • anonymous
how? :p
ganeshie8
  • ganeshie8
lets find BD first ?
anonymous
  • anonymous
okay
ganeshie8
  • ganeshie8
look at the other side, we have 12 and 18 there
ganeshie8
  • ganeshie8
on left side, we have 6 and BD
anonymous
  • anonymous
oh! so it would be 6/BD = 12/18?
ganeshie8
  • ganeshie8
thats it !
anonymous
  • anonymous
which equals 9!!
ganeshie8
  • ganeshie8
correct ! so strike off first two options
ganeshie8
  • ganeshie8
lets find BF also
anonymous
  • anonymous
BF equals 12...
ganeshie8
  • ganeshie8
careful...
anonymous
  • anonymous
not 12?
ganeshie8
  • ganeshie8
we have 24 and BF on onse side the other side we have 18 and 12
anonymous
  • anonymous
16 :) i multiplied wrong oops
ganeshie8
  • ganeshie8
Excellent !
anonymous
  • anonymous
yay!
ganeshie8
  • ganeshie8
good work :)
anonymous
  • anonymous
you too :)

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