anonymous
  • anonymous
How to graph ( -3, -1) and the slope is m= -1/5 please show me in details with explanation
Algebra
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
m=x/y just it !:)
anonymous
  • anonymous
you want the equation of the line?
anonymous
  • anonymous
Nope

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
so what is it? :D
anonymous
  • anonymous
Never mind I got it thank you
anonymous
  • anonymous
Nope
anonymous
  • anonymous
sorry I think m=x/y is discorrect!
anonymous
  • anonymous
say what do you want
anonymous
  • anonymous
I think I should graph the points then I take the slope either I go up or move right
anonymous
  • anonymous
Am I right?
anonymous
  • anonymous
yes you're right but you should use this formula: tan(Theta) = m
anonymous
  • anonymous
I m sure for this :)
anonymous
  • anonymous
there is no problem :)
anonymous
  • anonymous
x/y is incorrect,(y2-y1)/(x2-x1) is correct and then you can use this: y/x not x/y!
anonymous
  • anonymous
and besides that,line pasts two points not one points!
anonymous
  • anonymous
Why should I use tan (theta) =m
anonymous
  • anonymous
I take algebra 2 only
anonymous
  • anonymous
if you have "mesure of angle" you should use tan(theta) but if you know "2 points" you can use (y2-y1)/(x2-x1)
anonymous
  • anonymous
K I got u thnx!
anonymous
  • anonymous
You're welcome,Have a look at this too: http://en.wikipedia.org/wiki/Slope
anonymous
  • anonymous
http://upload.wikimedia.org/math/9/d/9/9d9e1aa5fab25d8dd659c0fb6e83234b.png http://upload.wikimedia.org/math/6/f/f/6ff91586a0e41749e401e86de39d5ade.png
anonymous
  • anonymous
got it?
anonymous
  • anonymous
Yup sure did :) thnx again
anonymous
  • anonymous
You're welcome:)
DebbieG
  • DebbieG
No need for trig in this problem. You are on the right track with plotting the point and then using the slope to get a 2nd point, but I worry what you mean by "either I go up or move right". :) You need to use the slope to determine the RISE and the RUN. You will EITHER move up or down the RISE, and you will EITHER move left or right the RUN. The combination depends on the sign of the slope. For positive slope, you want x and y to change in the same direction.... so you either go UP and RIGHT (both y and x increase) or DOWN and LEFT (both y and x decrease), in the amounts, respectively, of the rise and run. Either will work and will give you a 2nd points. For negative slope, you want x and y to change in opposite directions.... so you either go UP and LEFT, or DOWN and RIGHT. Once you have that 2nd point, draw the line through those 2 points. This method will work fine, although it isn't quite as "slick" as just cooking up the equation for the line. Then you can get any 2nd point on the line from the equation (like say, the y-intercept).
anonymous
  • anonymous
Wow!!! Ur good thanx!!! But what if my slope is negative like -3 should I do this -3/1 then find it?
DebbieG
  • DebbieG
Yes, you can interpret that slope as: \(\Large m=-3=-\dfrac{3}{1}=-\dfrac{rise}{run}\) So for each change of 3 units of "rise" (in the vertical direction, or in the y-coordinate, however you find it most natural to think of it), you will change 1 unit in "run" (in the horizontal direction, or in the x-coordinate). AND since slope is NEGATIVE, the changes must go in OPPOSITE directions. So from wherever your starting point is, you could either go: Up 3 and left 1 (increasing y, decreasing x) or Down 3 and right 1 (decreasing y, increasing x) Either works fine, they just give you two different options for the "2nd point".
anonymous
  • anonymous
OMG!!!! THANK YOOOUUU!!!!! I REALLY GET IT!!!
anonymous
  • anonymous
Could the second point be 3, -1?
anonymous
  • anonymous
@DebbieG
anonymous
  • anonymous
Could the second point be 3, -1?

Looking for something else?

Not the answer you are looking for? Search for more explanations.