At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
hi :) first multiply 4 and 12 :)
hi ok I get 48 which could possibly be -2 x24
but how to make that equal -19
okay, next step is to get the factor pairs of 48, that when you add it the result is -19 :)
what do you think would be the 2 factors?
that's where I am getting stuck
try -16, -3
that works thak you
so what would be your factors?
aha, what would be your final answer ?
that is not a factor :) ,that is addition, which likely you will combine like terms :)
1q-4(4q-3) is correct :)
Thank you for the explanation now I get how to do it. I tried another site and all they wanted to do is give me the answer which doesn't really help me learn
What I do is, I factor by grouping, do you want me to teach you that ? :)
if you don't mind
You're welcome :)
Okay here goes
Yeap np that method is called the umbrella method, easiest to learn until you learn how to just look at the problem and get the answer
4q^2-19q + 12 * first we multiply 4 and 12 we get 48, our goal is to find factors of 48 , that when we combine them we get -19 q , follow?
our factor pair is , -16 and -3 , which will give us -19 :)
that makes it seem easy now.
so when grouping , it goes like this , . . 4q^2 -16q -3q +12 -16 and -3 are our factors :)
we just expanded -19q :)
yes expanded it so that it would be a factor of both numbers
so by grouping we take the GCF of the First Two terms.
and we do the same for the other 2 terms :)
I wrote it down so I wont forget it. Thanks now to figure out how to do this one 2(a+b)^2-5(a+b)-3
what are we trying to do?
same thing factor it out completely
one moment :)
what do you think should be done first? exponent or constant?
is that what we are trying to factor?
no I was trying to figure it out 2(a+b)^@+(a+b)-6 I think I should athe a+b together correct
we have an exponent ^2
yes on the first a +b
yup, so we can't combine
to be honest I'm quite rusty on this, lol I'll seek help for you :)
ok I need all the help I can get:)
@DebbieG We may need your help :)
the problem is 2(a+b)^2-5(a+b)-3
uhmm red, I'm going to bed as, I have class tommorow, so nice time with you :) night
thank you for the help
Just start another session :)
ok I will