anonymous
  • anonymous
A line passes through (-4, 1), perpendicular to a line whose slope is -3/2 how am I supposed to graph it anyone could help
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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austinL
  • austinL
If two lines are perpendicular, their slopes are inverse opposites. \(m_1=\dfrac{a}{b},~m_2=-\dfrac{b}{a}\) And you also have the equation of a line (slope intercept form), \(y=mx+b\)
anonymous
  • anonymous
Ok
austinL
  • austinL
Did that make sense?

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anonymous
  • anonymous
Yea kinda
anonymous
  • anonymous
So if I plug it in like this... 1=-3/2x +(-4)
austinL
  • austinL
Wrong slope, \(m_1=-\dfrac{3}{2},~m_2=~?\)
austinL
  • austinL
And you plugged in the x value into the "b" spot, you plug it in for "x".
anonymous
  • anonymous
How do u get to kno the slope of the other line?
austinL
  • austinL
I told you how to find it up above. Inverse opposite of the given slope.
anonymous
  • anonymous
Oooh so if the slope is negative I change it to inverse its positive?
anonymous
  • anonymous
No its not making any sense now explain in a different way if u can
anonymous
  • anonymous
Hello?
anonymous
  • anonymous
@hubbabubba : When tow line are perpendicular we have : m.m2=-1 So the slope is 2/3 And we have : y=2/3x But what is the (-4,1) ? Look : -4/1=-4 So we should be have d too . Now can u answer d ?:)
anonymous
  • anonymous
Where did u get d from???
anonymous
  • anonymous
d is the piont the line and y .|dw:1062912091284:dw|
anonymous
  • anonymous
Wait ... What is the (-4,1)in the question ???
anonymous
  • anonymous
Its a line that passes thro tha point
anonymous
  • anonymous
It s a point ?
anonymous
  • anonymous
@hubbabubba
anonymous
  • anonymous
Yes
anonymous
  • anonymous
So its ok ! Now u should use this formula : y-y2=m(x-x2) X1=-4 Y2=1 OK?:)
anonymous
  • anonymous
K
anonymous
  • anonymous
So its gonna be
anonymous
  • anonymous
1 - y2 = -3/2 (-4 - x2) right?
anonymous
  • anonymous
Excelent but I said to you : x2=-4 y2=1 2 is just a number no *2 ...
anonymous
  • anonymous
Ik it x2
anonymous
  • anonymous
Y x2 n y2 Y not x1 n y1
anonymous
  • anonymous
No diffrence 1or2 are just name . you should get the things true in formula means get the (-4,1)of point than y and x not affter them ! Because your answer will be fall :) Now answer again :)
anonymous
  • anonymous
Y - 1 = -3/2 ( x + 4 ) right?
anonymous
  • anonymous
Exelent !:)
anonymous
  • anonymous
Then y = -3/2x + 6 right? As in y=mx +b
anonymous
  • anonymous
But the slope was 2/3 forgot ?
anonymous
  • anonymous
Look : y-1=2/3(x+4) OK ??!:)
austinL
  • austinL
A line passes through (-4, 1), perpendicular to a line whose slope is -3/2. \(m_1=-\dfrac{a}{b}=-\dfrac{3}{2}\) \(m_2=-(-\dfrac{b}{a})=-(-\dfrac{2}{3})=\dfrac{2}{3}\) Then we have the equation of a line, \(y=mx+b\) With the point, \((-4,1)=(x,y)\) which we then plug into the equation to solve for the y intercept b. \(y=mx+b\rightarrow1=(-4)(\dfrac{2}{3})+b\) \(b=\dfrac{11}{3}\) So therefore we have, \(y=\dfrac{2}{3}x+\dfrac{11}{3}\)
anonymous
  • anonymous
Okay
anonymous
  • anonymous
@hubbabubba :Understand and got it ?
anonymous
  • anonymous
No
anonymous
  • anonymous
did u get my formula ?
anonymous
  • anonymous
How did u get 11/3 ? @ austinL
anonymous
  • anonymous
And no ur making it complicated for me btw @E.ali
anonymous
  • anonymous
How did u get 11/3 ? @ austinL
anonymous
  • anonymous
@austinL
austinL
  • austinL
You simply solve for b in that equation.
anonymous
  • anonymous
Dont think about 11/3 . I m not sure about it :) Can you write it by the formula ?
austinL
  • austinL
\(y=mx+b→1=(−4)(\dfrac{2}{3})+b\)
anonymous
  • anonymous
Yea i did that
anonymous
  • anonymous
Wat formula are u talking abt? Im taking algebra 2 here
anonymous
  • anonymous
@austinL : I think I m answering friend !:)
anonymous
  • anonymous
@hubbabubba :about about it :y-1=2/3(x+4) OK?
anonymous
  • anonymous
For the 3rd time I got the equation I solved it but it didnt give me 11/3
anonymous
  • anonymous
So u multiply ( -4 ) × 2/3 right?
austinL
  • austinL
\(-4\times(\dfrac{2}{3})=-\dfrac{8}{3}\) \(1+\dfrac{8}{3}=\dfrac{3}{3}+\dfrac{8}{3}=\dfrac{8+3}{3}=\dfrac{11}{3}\)
anonymous
  • anonymous
Oh k makes sense now thnx austin
austinL
  • austinL
No problemo.
anonymous
  • anonymous
Ok then so how do I graph the equation n the point?

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