taylormarie213
  • taylormarie213
John has 51 coins. Dimes and quarters worth $9.60. How many of each coin does John have?
Pre-Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
divide .25 (quatrer) into $9.60 dose that get yo started??
anonymous
  • anonymous
x are dimes and y are quarters when you add all values you get 10x+ 25y= 9.60 when you add your quarters and dimes you get 51 coins x+y=51
anonymous
  • anonymous
You now have a system of equations. You can either use substitution or addition of subtraction of the equations.

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anonymous
  • anonymous
use substitution method
taylormarie213
  • taylormarie213
ah i'm braindead. Can you show me how to set up the substitution or addition of subtraction equations? please?
anonymous
  • anonymous
i'm sorry i have to go ill try to help you later if ur answer didn't get answered but i think someone else might help you sorry
anonymous
  • anonymous
x+y=51 isolate for x x=51-y Now replace everything on that x with 51-y 10x+ 25y= 9.60 turns into 10(51-y)+25y=9.60 Solve for y now. Once you find y use that value and plug it back in into any equation then solver for x
taylormarie213
  • taylormarie213
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anonymous
  • anonymous
sorry its suppose to be .10*(51-y)+.25*y=9.60 you should get y=30
taylormarie213
  • taylormarie213
thank you my friend helped me :]

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