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It seems like there may be a variable missing.
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That looks much better.
I've never solved a systems of equations with squared terms so don't take anything I say as absolute...
I would solve the bottom equation for \(x^2\) and substitute into the other equation.
I have already attempted it, but I am stumped b/c everything is ^2 so it is difficult to simplify
I think, if you solve for \(x^2\) then substitute that in the other equation you should be able to solve for x.
\(3y^2-x^2=3\) Solve for \(x^2\)
\(-x^2=3-3y^2\) Multiply through by -1
\(x^2 = -3+3y^2\) Then substitute that into the other equation for \(x^2\).