anonymous
  • anonymous
Find all points on the x-axis 5 units away from the point (4, 3).
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
DebbieG
  • DebbieG
Use the distance formula: \[\Large d=\sqrt {(x_1-x_2)^2+(y_1-y_2)^2}\] This the points you are interested in are ON the x axis, you know what their y-coordinate is, right? And the distance from your given point is d=5. so you have: \(\Large 5=\sqrt{(x_1-4)^2+(y_1-3)^2}\) Once you fill in the correct \(y_1\) value, you will be able to solve that for the two x coordinates that give you the distance of 5 from the given point. :)
anonymous
  • anonymous
Is y(sub 1) equal to zero?
anonymous
  • anonymous
Yes. \(y_1=0\).

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Is this the distance formula or what @DebbieG attached?
anonymous
  • anonymous
You have the correct formula now. I'm not sure if it really makes a difference. I will run a few examples to check.
anonymous
  • anonymous
Reversing the points make the values inside the parenthesis negative but that is irrelevant because the number is being squared and becomes positive.
anonymous
  • anonymous
Ok, so it's one way or the other. Thanks!
anonymous
  • anonymous
|dw:1378600897652:dw|
anonymous
  • anonymous
Yes, and solve for x. \(\Large 5=\sqrt{(x_1-4)^2+(0-3)^2}\)
anonymous
  • anonymous
\[5=\sqrt{x _{1}+16+9} ?\]
anonymous
  • anonymous
doesn't quite work that way. Since the y coordinates are both constants so you can combine them before you square it. For the x coordinates, you have to FOIL.
anonymous
  • anonymous
25=x^2-8x+25
DebbieG
  • DebbieG
Thanks for grabbing this, @gypsy1274 ! Sorry I didn't get back here... but yes, the order of the points in the distance formula makes no difference. It doesn't even matter which point is the "1's" and which is the "2's", you will get the same result. The distance between 2 points doesn't depend on the "direction" in which you compute it. :)
anonymous
  • anonymous
Teamwork! Yeah!!!
anonymous
  • anonymous
@sportcraze0 Great work, now move all terms to one side and factor.
anonymous
  • anonymous
0= x^2-8x
anonymous
  • anonymous
Exactly. Now factor.
anonymous
  • anonymous
Almost done. I have x(x-8)=0, so x=0 and x=8?
anonymous
  • anonymous
That is the answer that I got as well. Great Job!
anonymous
  • anonymous
Thank you @gypsy1274 and @DebbieG !!!

Looking for something else?

Not the answer you are looking for? Search for more explanations.