Suppose that you toss a rock upward so that it rises and then falls back to the earth. If the acceleration due to gravity is 9.8 m/sec2, what is the rock’s acceleration at the instant that it reaches the top of its trajectory (where its velocity is momentarily zero)? Assume that air resistance is negligible.
Stacey Warren - Expert brainly.com
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Regardless of where the rock is in its flight path, the force of gravity is still acting on it. So your rock, even when it's velocity is momentarily at 0m/s, is still experiencing a downward acceleration of 9.8m/s^2 (assuming air resistance is negligible).
Think about this: If there were no acceleration at that point, there would be no force to cause it to come back down.
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if no acceleration then it would not come back down..? so The rock has a downward acceleration of 19.6 m/s2? would it double while coming back down ?
At the top of its flight path, the rock is moving at 0 m/s...for an instant. The only reason it doesn't stay at 0m/s is because the force of gravity is still acting on it.
The acceleration of the rock is a constant 9.8 m/s^2 downward for the rock throughout its flight. It doesn't double...that would require more energy.
oh so it stays the same..would it always stay constant?
If there are no other forces acting on the rock then the only force will be the force of gravity...which will be essentially constant (unless you through it REALLY high...miles).
*throw* I mean
ohh thank you
i get it but not all the way, do you have an example?
This may help: