Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

Help! The question is attached!

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

Attempt to solve for x! (4,y) and (7,-6); slope:-4
\[\frac{ -6-y }{ 7-4 }=-4\] \[\frac{ -6-y }{ 3 }=-4 \] I just set it up like the normal slope equation, (y2-y1)/(x2-x1). Now just see if you can solve for y.
Olay, let me try it out for myself to see if I understand it

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Alrighty.
Wait, I get -6 / 3 how did you get -4?
You said the slope = -4, right? Well, the result of (y2-y1)/(x2-x1) is slope. But we already have the slope, so I just set the equation equal to -4.
Ahhhhhh okay I see how you set it up!
And then you subtract the bottom, correct?
Yeah, which left me with \[\frac{ -6-y }{ 3 }=-4 \]Would you know how to use that to solve for y?
My guess is that I multiply -6 and 3
Just multiply both sides by 3 to start.
That will cancel the 3 out of the denominator of the fraction.
So would it be 18+3y=-4
Nah. Okay, so we multiply both sides by 3 and it looks liek this: \[\frac{ 3(-6-y) }{ 3 }=-4(3)\]From here, the 3's on the left cancel out and -4 and 3 multiplies to get: \[-6-y = -12 \] Kinda see why?
Yea aha I sorta do, it's because I got -18-3y=-12 when I multiplied it by 3
Yeah, but you dont multiply the -6 and the -y by 3. Because you have a 3 on top and bottom, they cancel out and become 1. That is the whole purpose of multiply by 3 is because itll get rid of the denominator. It's just like if we had: \[\frac{ x }{ 3 }=3 \]Because x is divided by 3, to get it by itself we do the opposite operation and multiply by 3. |dw:1378605836732:dw| Same thing with our problem: |dw:1378605874087:dw|
Ahhhhhh okay I see now! And then after I get -6-y=-12 I add 6 to both sides
Right.
When I divide y to both sides, would I be dividing -y or just y?
Well if you have -y = -6, it does no good to divide by y or -y. If you divided by -y you get: \[1=\frac{ 6 }{ y } \] You just want to divide by -1 is all to get y by itself.
And the final answer will be y=6
Bingo. Can even test it :3 \[\frac{ -6-6 }{ 7-4 }=\frac{ -12 }{ 3 }=-4 \] So yep, works :3
Thank you much, you explained very well unlike most people here :D do you have time to help me with another 3 problems I had trouble with?

Not the answer you are looking for?

Search for more explanations.

Ask your own question