anonymous
  • anonymous
Find the limit
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
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anonymous
  • anonymous
Psymon
  • Psymon
First split it into two fractions, then know that: \[\lim_{x \rightarrow 0}\frac{ \sin(x) }{ x }=1 \]As long as the angle of sin and the thing in the denominator match, you can say that is 1.
anonymous
  • anonymous
@Psymon So far Im at this point, would the answer be 2?
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Psymon
  • Psymon
Not quite. Usually they have you do a trick to force what you have to look like: sinx/x Now, x can be anything, as long as the angle of sin and the number in the denominator match. so yes, you have that left fraction that reduced to 2, but now you need to mess with the right fraction. \[\frac{ -\sin(kx) }{ x }\]So since the angle of sin is kx, we need the denominator to be kx. So what do you have to do to get a k in the bottom?
anonymous
  • anonymous
@Psymon Ah I see. I would multiply k, Would the multiplication carry over to 2x/x as well?
Psymon
  • Psymon
nah, you dont need to do that, just keep it on the one fraction. So you would multiply top and bottom by k |dw:1378610673553:dw|
anonymous
  • anonymous
@Psymon That makes a lot of sense! I understand how you did that. Thank you for your help! Really appreciate it :)
Psymon
  • Psymon
Yeah, np ^_^
goformit100
  • goformit100
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