Firejay5
  • Firejay5
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Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Firejay5
  • Firejay5
Firejay5
  • Firejay5
@campbell_st I am not sure how to do this and I am not for sure if you learned this in Australia
anonymous
  • anonymous
P and Q are complementary, therefore P+Q = 90

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anonymous
  • anonymous
Substituting in our values for P and Q, we get: \[(2x+25)+(4x+11) = 90\]
anonymous
  • anonymous
Rewriting: \[6x + 36 = 90\] \[6x = 54\] \[x = 9\]
anonymous
  • anonymous
Did you want c too?
Firejay5
  • Firejay5
yes
anonymous
  • anonymous
AEB and AED are supplementary. Therefore: \[AEB + AED = 180\]
anonymous
  • anonymous
Substituting in: \[(9x)+(5x+68) = 180\]
anonymous
  • anonymous
Rewriting: \[14x + 68 = 180\] \[14x = 112\] \[x = 8\]
anonymous
  • anonymous
\[AEB = 9x = 9(8) = 72\] \[AED = 5x+68 = 5(8) + 68 = 108\]
Firejay5
  • Firejay5
What about A and B how would that start
anonymous
  • anonymous
Do you mean questions a and b?
Firejay5
  • Firejay5
yes sir
anonymous
  • anonymous
Have you posted them?
Firejay5
  • Firejay5
anonymous
  • anonymous
Draw a picture: |dw:1378616496333:dw|
anonymous
  • anonymous
Sorry, L was cut off |dw:1378616602159:dw|
anonymous
  • anonymous
L is a bisector. Therefore: \[LFM = AFL\]
anonymous
  • anonymous
Are you able to do the substitutions and solve the equation for x?
Firejay5
  • Firejay5
Probably
anonymous
  • anonymous
Can you do it now tell me what answer you get?
Firejay5
  • Firejay5
so A & B work together basically
anonymous
  • anonymous
They use the same diagram, but are not the same problem
anonymous
  • anonymous
\[AFM = 2AFL\]
Firejay5
  • Firejay5
like give me a small hint on how to solve it
anonymous
  • anonymous
They are neither supplementary or complementary
anonymous
  • anonymous
You use the fact that L bisects AFM to solve the problem
anonymous
  • anonymous
Because L is a bisector of AFM: \[LFM = AFL\]
Firejay5
  • Firejay5
I think I have the answer
anonymous
  • anonymous
Go ahead
Firejay5
  • Firejay5
A. 6; 70;70 B. -4; -40
Firejay5
  • Firejay5
I am not for sure if it's correct
anonymous
  • anonymous
A is correct, but not B.
Firejay5
  • Firejay5
What did you do to B?
Firejay5
  • Firejay5
I did 6x - 2 = 4x - 10 was that wrong
anonymous
  • anonymous
Be careful, AFM is the whole angle, and AFL is just one half. \[AFM = 2AFL\]
Firejay5
  • Firejay5
6x - 2 = 2(4x - 10)
Firejay5
  • Firejay5
How do you solve it?
Firejay5
  • Firejay5
@zepdrix I need help on B.
Firejay5
  • Firejay5
Firejay5
  • Firejay5
@MrMoose How do you solve it (B)?
anonymous
  • anonymous
So you wrote down the correct equation: \[6x-2 = 2(4x-10)\]
anonymous
  • anonymous
Distributing: \[6x-2 = 8x - 20\]
anonymous
  • anonymous
Can you solve it from here?
Firejay5
  • Firejay5
B. 9;103 <--- Is that right?
anonymous
  • anonymous
x is 9, but LFM is not 103
Firejay5
  • Firejay5
where do you plug in 9 at
anonymous
  • anonymous
It asks us to find LFM, which is equal to AFL
anonymous
  • anonymous
So if we find the value for AFL, we will also find the value of LFM
anonymous
  • anonymous
So plug in x to the equation for AFL
Firejay5
  • Firejay5
26 or 106
anonymous
  • anonymous
Why do you say or?
Firejay5
  • Firejay5
do you plug 9 into the equation on B
anonymous
  • anonymous
You plug 9 into the equation for AFL in B, yes
Firejay5
  • Firejay5
then the answer is 26
anonymous
  • anonymous
Yes, it is.
Firejay5
  • Firejay5
thank your @MrMoose You helped me so majorly on this
anonymous
  • anonymous
You are welcome
Firejay5
  • Firejay5
I understand it a whole lot better than before

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