A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
I know this is not math but whatever. If the mass is 1.16 and the volume is 8.5 what is the slope?
anonymous
 3 years ago
I know this is not math but whatever. If the mass is 1.16 and the volume is 8.5 what is the slope?

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0In my HW it says to find the slope it's (change in mass)/(change in volume)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Luigi0210 help please?

Luigi0210
 3 years ago
Best ResponseYou've already chosen the best response.0Do you know the changes?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What do you mean by that?

Luigi0210
 3 years ago
Best ResponseYou've already chosen the best response.0Do you only have one set of values?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh no there's more. Want me to put them up?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Label 1) mass: 1.16 g volume:8.5 . Label 2) mass:0.98 volume: 7.2. Label 3) mass: 1.13 volume:10.0 . Label 4) mass: 0.69 volume: 6.2. Label 5) mass: 0.83 volume:6.0. Label 6) mass:1.45 volume: 12.9. Label 7) mass: 0.88 volume: 7.9. Label 8) mass: 1.03 volume: 7.5. Label 9) mass: 0.74 volume: 5.4. Label 10) mass: 1.02 volume: 7.5

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Sorry I couldn't lined them up well I'm on my iPad right now

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what happens if you treat the mass as the x coordinate and the volume as the y coordinate?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0But that'll mean graphing all 10 of them

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@dumbcow @dan815 got any ideas how to do this?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Luigi0210 don't worry(:

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0tryin to find a website the will plot all the points

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.0kant, use this site, it's quite good :) https://www.desmos.com/calculator

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0looks like the slopes are about the same for a series of points...not sure what the question is looking for

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thanks zepdrix i'll check that site too...the one i found called http://openstudy.com/study#

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm missing clone wars for this!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@kantalope lol my bad and how does this help me find what I'm looking for?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0typically when you are looking for slope you are looking for the change in whatever based on the change in the other thing.....these changes aren't a straight line. what else does the question have?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it is a bit confusing that a slope can be asked when mass and volume are given. However, if the slope is meant to mean density, then I will say the slope= mass/volume.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if the data has a function we can find the variable slope based on the derivative of the function

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0heh  I'll bet I'm supposed to be able to figure out this kind of problem at the end of the semester not the beginning...and the martini I just finished in not helping...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm rearranging the data on the graph...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0http://mcpchemistry1.wikispaces.com/file/view/HW4%20%20Density%20Graph%20Practice%20201314.doc/447730728/HW4%20%20Density%20Graph%20Practice%20201314.doc here is my HW, the question is on the last page

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The points are all squirrely so a serious person would do some stat regression to find the mean

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ah ha...which is exactly what the graph was finding

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I think your looking at the wrong page, it's the very last one

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0right so my pictures were plots of the data that we were given...it is all wonky

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If we were measuring stuff that had a consistent mass to volume ratio the line would be nice and straight....the more stuff we had the more it would weigh yea?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah it is all "wonky" ughhh this is irritating

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that's ok that is how real data works

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah, I know what your saying

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You sure I'm not just suppose to divide or subtract?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so our data is sloppy could mean a couple of things like the hint suggests  maybe some of the chunks we are looking at are real rocks and some are plastic fake rocks

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0nah if you were serious about this data you would plot it out like we did and look if it was in straight lines...if it was not you would do a process called regression to find the average slope between the plot points

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0right so some of metal is real and some of it isn't or some of the metal is a different kind or you could just be kinda sloppy in measuring the volume or the mass...rounding up sometimes and rounding down others or if you have different people doing the measuring the data will get screwy

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Becauseatfirst I taught I was only suppose to divide and ill get the answer, but apparerently not

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So for the last page you can paste in the plots in the pictures and a hypothesis is that the measurements are not consistent and that there seems to be two different trend lines in the data so there are probably two different kinds of metal in the sample with two densities regression wiki: http://en.wikipedia.org/wiki/Least_squares

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If you did just divide each set of points to get a series of numbers....I'll bet you get two sets of answers...lemme check that

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0actually turns out that there are more like 3 sets of ratios  .14 is the answer to 3 samples .111 to three and .138 to three more < this also points to something funny with the data if the ration of volume to mass was the same all the samples would have basically the same well ratio ya so just dividing would show something but the graph makes it easier to see

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Can you explain in a different way, she cant understand

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If the samples were consistent  all made of the same stuff  if you had more stuff it would weigh more....a big gold coin has more mass (weighs more) than a small gold coin...and that change in size and mass would be consistent. A coin that is twice as big would weigh twice as much....does that make sense?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, I do understand that thAt was one of the questions lol

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so if i started handing you coins that were twice as big but didn't weigh twice as much ...you would say "dood, you are rippin me off, these are not gold coins" that is what the first graph is showing ....there are four coins in the top line with a certain volume to weight ratio (slope) and then 6 coins in another line with a different volume to weight ratio(slope)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Somehow I think I'm just suppose to divide, and I'm just complicating myself!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well number 2 on the second to last page says graph it....so there is that

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah and I already graphed it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and the graph show some dots that make a line and some other dots that make a different line?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so the last question says to calculate the slope of each of those lines m= (y1y0) / (x1x0) if you pick any two points on the two lines you can get the slope

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Can you do the first one as an example? Please

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok top line the first point is (.69, 6.2) and another point on that line looks like (1.45, 12.9) would you agree?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0y1= 12.9 y0 = 6.2 x1= 1.45 x0 = .69 6.7/.76 = 8.82

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0No it's suppose to be 1.16 and 8.5

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the points on the other line are (0.74,5.4), ( 0.83,6.0), ( 0.98, 7.2), ( 1.02 ,7.5), ( 1.03, 7.5), (1.16,8.5) you can use any of those points to calculate the slope of the second line

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I started with the top line....that point is on the lower line...you can go with whatever one first

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So I'll divide it like 1.16/8.5 correct?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0not if you want to calculate the slope like the last question asks...dividing will just get you the ratio not the slope...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I made the graph bigger so it is easier to see the two different lines....we are looking for the slope of those two lines I think that the instructions are confusing as they ask for the change in mass over the change in volume....simply dividing is not the change....it is just the mass over the volume...in order to get the change part you have to do the y1y0 thing

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I hope that means you are going ...ah, I get it rather than ah @$%$ it =)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ahhhh crap? Lol I think I'm complicating it more that I should that's why , but that's all

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0k gl im out its really late here

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah get some sleep goodnight
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.