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y'+y\cot(x) = \csc(x)
I think you'd find the homogeneous solution and then the particular one.
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it's linear equation so I'd use an integrating factor, I'd start by dividing each term by sin x.
Now from here we need ti find the integrating factor. The integrating factor is e to the integral of the coefficient of the y term
Sine the y term is multiplied by cot x we need to integrate that, how should we integrate cot x?
I'd start by writing it in terms of sin and cos.
the integral of cot x should be memorized - it's something like -ln|sin x|. Cause like, yolo
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