anonymous
  • anonymous
what is the answer of cot/cos ;csc
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SOLVED
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schrodinger
  • schrodinger
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Luigi0210
  • Luigi0210
\[\frac{\cot x}{cosx}=\frac{\cos x}{\sin x}*\frac{1}{cosx}=\frac{1}{sinx}=cscx\]
DLS
  • DLS
That was amazing @Luigi0210 !
Luigi0210
  • Luigi0210
Naw, pretty simple/basic if you ask me :3

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DLS
  • DLS
That was supposed to be sarcastic XD
Luigi0210
  • Luigi0210
I see >.>
anonymous
  • anonymous
nice one luigi thank you for your answer
anonymous
  • anonymous
how about this what is the answer 1+cot^2 theta /sec ^2 theta ; Cot ^2 theta
Luigi0210
  • Luigi0210
I'll wait for DLS :3
DLS
  • DLS
\[\LARGE \frac{1+\cot^2 \theta} {\sec ^2 \theta}=\frac{cosec^2 \theta}{\sec^2 \theta}=\frac{\frac{1}{\sin^2 \theta}}{\frac{1}{\cos^2 \theta}}=\]
DLS
  • DLS
phew,this was tough :3
DLS
  • DLS
\[\Huge 1+\cot^2 \theta=cosec^2 \theta\] iis the property here
anonymous
  • anonymous
that is the final answer?
DLS
  • DLS
\[\LARGE \frac{1+\cot^2 \theta} {\sec ^2 \theta}=\frac{cosec^2 \theta}{\sec^2 \theta}=\frac{\frac{1}{\sin^2 \theta}}{\frac{1}{\cos^2 \theta}}=\] u cant solve it now??
Luigi0210
  • Luigi0210
The final answer can be found deep within your soul.. you just have to look deep enough xD
anonymous
  • anonymous
ah ok but we don't have any give that is the only given
anonymous
  • anonymous
(1+cos theta) (1-cos theta) ; sin ^2 theta
DLS
  • DLS
@luigi0210 ? :P
DLS
  • DLS
you wanna do it?
DLS
  • DLS
@frincess use this property \[\LARGE (a+b)(a-b)=a^2-b^2\]
anonymous
  • anonymous
DLS ur so smart in math
Luigi0210
  • Luigi0210
Oh, yea give me the headache problem >.> Distribute and you get: \[(1-\cos^2x)=\sin^2x\]
DLS
  • DLS
\[\Huge \cos^2 \theta+\sin^2 \theta=1\] is the property here
DLS
  • DLS
why is all this happening on OS feedback BTW?
anonymous
  • anonymous
1+tan^2theta/ csc^2 : tan^2 theta
DLS
  • DLS
\[\Huge 1+\tan^2 \theta=\sec^2 \theta\] is the property here
anonymous
  • anonymous
how did u get that can u tell me how to get a solution
Luigi0210
  • Luigi0210
One question at a time D:
goformit100
  • goformit100
"Welcome to OpenStudy. I can guide regarding this useful site; ask your doubts from me, for it you can message me. Please use the chat for off topic questions. And remember to give the helper a medal, by clicking on "Best Answer". We follow a code of conduct, ( http://openstudy.com/code-of-conduct ). Please take a moment to read it." SIR OR MADAM. please post the Question in the correct Section.
Preetha
  • Preetha
Folks the proper place for this question is in Math. Next time....
DLS
  • DLS
its a standard property @frincess and yet again I advice you to post in the MATH section
Luigi0210
  • Luigi0210
It wasn't me Preetha >.>
DLS
  • DLS
@Preetha already posted :D
anonymous
  • anonymous
oh in mathematics who is engineering her

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