anonymous
  • anonymous
Differentiate the Functions. f(u)= (ln(u)/1+ln(2u))
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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inkyvoyd
  • inkyvoyd
is this ln(u)/1?
inkyvoyd
  • inkyvoyd
cause ln(u)/1=ln(u)...
anonymous
  • anonymous
f(u)=ln(u)/(1+ln(2u))

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inkyvoyd
  • inkyvoyd
okay. for these problems I'd probably brute force it out with the quotient rule, but there maybe a better way...
DebbieG
  • DebbieG
I was going to say quotient rule, too. YOu could rewrite the den'r as 1 + ln2 +ln(u) for ease in the differentiation step. Avoids the chain rule.
inkyvoyd
  • inkyvoyd
lol, forgot the rules for logarithms :S
DebbieG
  • DebbieG
Oh right, lol... you had me convinced, but yeah, the product rule, not the exponent thing, applies here. :)
inkyvoyd
  • inkyvoyd
so glad I'm out of calculus hehe - no loggy log laws in discrete
anonymous
  • anonymous
so can someone work it out for me because I keep trying and am not getting the right answer
DebbieG
  • DebbieG
How about if you show us what you did, and we can tell you where you're going wrong.
anonymous
  • anonymous
ill try again later. I dont feel like typing it all out

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