anonymous
  • anonymous
if the picture below is y = f(x) then graph the function if its function is now y = f(x-3) + 2
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
jim_thompson5910
  • jim_thompson5910
in general, y = a*f(x-h) + k shifts the graph of y = f(x) and h takes care of the horizontal shifting and k pellets the graph up and down the 'a' stretches or compresses the graph
jim_thompson5910
  • jim_thompson5910
so what are h and k in this case?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
h is 3 and k is 2
jim_thompson5910
  • jim_thompson5910
so this means that you start with y = f(x) and to get y = f(x-3) + 2, you shift f(x) 3 units to the right (since h = 3) and 2 units up (because k = 2)
anonymous
  • anonymous
oh! cause i though it was 3 units to the left ok i understand :) can you help me with another graph question?
jim_thompson5910
  • jim_thompson5910
no because it's x-h and not x+h, it's going to be the opposite
jim_thompson5910
  • jim_thompson5910
and sure
anonymous
  • anonymous
ok ill post it as a separate question, give me a sec
jim_thompson5910
  • jim_thompson5910
ok

Looking for something else?

Not the answer you are looking for? Search for more explanations.