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Just the Slope-intercept form atm, I said the answer was y = 3(0) + 1 is that correct?
Augh I didn't think so, could you help me please?
replacing (0) with (pi/2) should be most easy task here so that slope = tan theta = tan pi/2 = undefined
Wait would it be y = 3x + 1?
for x-intercept to be 7,your equation should give x=7 on substituting y=0
wait you're confusing me
Where did you get the 7 from?
by definition, vertical lines have undefined slope they're of form x=k
my teacher hasn't taught me tan and all of that stuff yet, I'm refreshing my memory of the basics of slope and graphing. She just wants me to convert the two points into the three forms
ohk, since x-intercept is here 7, we can blindly write the equationas x=7 :)
first find the slope
The slope is 3
now just convert them to the asked forms
point slope form : y-y1 = m(x-x1)
(4 – 1) = 3(1 – 0) Point-slope form y = 3x + 1 Slope-intercept form I don't know how to do Standard form
noo (y – 1) = 3(x – 0) Point-slope form y = 3x + 1 Slope-intercept form
How come the x and y aren't in there? and how do you know which points to use?
you can use any point
Same thing for the Standard form? I can use any point?
Point slope form :- equation when using , point (1, 4) and slope 3 :- y-4 = 3(x-1) equation when using , point (0, 1) and slope 3 :- y-1 = 3(x-0)
notice that both equations give us same thing after simplification
THat's how you know it is correct?
Okay:D How do I solve for standard form?
start wid point-slope form y-1 = 3x
change it to the form , Ax+By = C
Okay, one second
So y - 1 = 3x +1 + 1 y = 3x + 1 -3x -3x -3x + y = 1 Is that correct?
Correct :) also you may write it as, 3x-y = -1
np :) you did awesome work =))