anonymous
  • anonymous
I am a little stuck on part b. The question shows a picture of a mass spectrum for 1-bromopropane. It then has the following questions: 3a) Identify the species responsible for signals m/z 124, 122, 81, 79, 43 and 29. (Completed) 3b) Write an equation for the formation of each species: So far i have gotten C3H7Br -> [C3H7]^+ +Br(radical) + e- But i am unsure about the rest. Any feedback is greatly appreciated! :)
Chemistry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
The question starts with 1-bromopropane so I am unsure about the fragments
abb0t
  • abb0t
That means you have: |dw:1378668016880:dw|
anonymous
  • anonymous
I am confused as how that links into the question as it is to do with peaks on a mass spectrum graph, would it be more helpful if i posted a picture of the question?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
as to**
abb0t
  • abb0t
the formation of 1-bromopropane?
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
That is the whole question
abb0t
  • abb0t
Yes, well each mass corresponds to the intermediate steps towards the formation. Such as cation formation...and so forth.
anonymous
  • anonymous
yes so for example [C3H7]+ would be 43
anonymous
  • anonymous
and 29 would be [C2H5]+
abb0t
  • abb0t
Yes.
anonymous
  • anonymous
The point i get confused at is when you have to write the whole equation, i can get the fragments but not the rest of the equation. So one of the equations would be: C3H7Br --> [C3H7]+, + Br(radical) + e- But what would it be if the fragment was [C3H6Br]+ then what would the other products be?
anonymous
  • anonymous
Would it be [C3H6Br]+ + an e-? or would there be other products too?

Looking for something else?

Not the answer you are looking for? Search for more explanations.