anonymous
  • anonymous
question 5, help please
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
jim_thompson5910
  • jim_thompson5910
for each one, you can plot a bunch of points and draw a curve through those points
jim_thompson5910
  • jim_thompson5910
so for instance, if x = 0, then y = x^3 y = 0^3 y = 0 so (0,0) is on y = x^3 and... if x = 1, then y = x^3 y = 1^3 y = 1 and (1,1) is also on y = x^3 if x = 2, then y = x^3 y = 2^3 y = 8 which means (2,8) is also on y = x^3

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anonymous
  • anonymous
is there any quicker way? that seems very tedious?
jim_thompson5910
  • jim_thompson5910
so plot those points (and more for better accuracy), then draw a curve through them to graph the function
jim_thompson5910
  • jim_thompson5910
well you could graph the basic shape from memory, the equation y = x^3 is a cubic which looks like this |dw:1378668014550:dw|
anonymous
  • anonymous
ok thx :) ill just learn off the shape of those graphs then, thx a bunch !
jim_thompson5910
  • jim_thompson5910
they don't have to be accurate since they rough sketches, so you can use this quicker method you're welcome
anonymous
  • anonymous
ok thx again!
jim_thompson5910
  • jim_thompson5910
np

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