anonymous
  • anonymous
How do you graph the solution to the system of linear equalities y
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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jim_thompson5910
  • jim_thompson5910
to graph y < x+2, you step 1) graph the line y = x + 2 step 2) make this a dashed line (since there is NO line under the inequality sign) step 3) shade below the dashed line (because the inequality sign is a less than sign)
jim_thompson5910
  • jim_thompson5910
you repeat the same steps for y <= -3/4x and you make a note where the two shaded regions overlap
anonymous
  • anonymous
@jim_thompson5910 to graph the line y=x+2, would i just go up 2 spaces like this?|dw:1378667903204:dw|

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jim_thompson5910
  • jim_thompson5910
good, the y intercept is (0,2), then you go up 1 and over 1 (since the slope is 1/1) to get to the next point (1,3) |dw:1378668100531:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1378668131267:dw|
jim_thompson5910
  • jim_thompson5910
then you turn that into a dashed line
anonymous
  • anonymous
thank you so much @jim_thompson5910 ! for \[y \le -3/4x\] how would i find the y-intercept if i know the slope is 3/4?
jim_thompson5910
  • jim_thompson5910
when you plug in x = 0, what do you get for y?
anonymous
  • anonymous
would it be 0 because it is multiplying 3/4 with 0?
jim_thompson5910
  • jim_thompson5910
yep
jim_thompson5910
  • jim_thompson5910
so the y-intercept is (0,0)
jim_thompson5910
  • jim_thompson5910
so you start at (0,0) then you go down 3, and to the right 4 to land at (4,-3) plot those two points, draw a line through them the line is solid this time because there is an underline under the inequality sign
anonymous
  • anonymous
would the shading look like this?|dw:1378668586758:dw| @jim_thompson5910
jim_thompson5910
  • jim_thompson5910
you shade below the graph of y = -3/4x because the inequality sign for y <= -3/4x is a "less than or equal to sign"
jim_thompson5910
  • jim_thompson5910
so it should look like this |dw:1378668832880:dw|
jim_thompson5910
  • jim_thompson5910
ignore the red shading in my diagram
anonymous
  • anonymous
thank you so much @jim_thompson5910, I really appreciate the help!
jim_thompson5910
  • jim_thompson5910
you're welcome

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