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be sure to fix the mistake in your previous problem.
i got 2lnx+3lny-3ln2
i did, thank you
just no -1 in front right?
in the other problem, I notice you added the two terms in the bottom. you should multiply them.
for this one, you have to look for terms that are *multiplied* (adding *inside* a log is not useful) here you have x^2 * (y-2)^2 you can split the multiplication into the sum of two logs
then you can move the exponents outside the logs you end up with just two terms.
i lost internet but ii am back
thank you for help
2lnx times 3ln(y-2)
close. the multiplication *inside* the log becomes ADD of logs 2lnx + 3ln(y-2)
darn so close thanks for all your help
if it helps to remember, people invented logs and used them to change complicated multiplication problems into addition problems given 12345 * 789011 they changed both into logs using a table added the logs then looked up the "anti log" log( 12345 * 789011) = log( 12345)+log (789011) adding was easier than multiplying.
just be thankful you can use a calculator. Using logs was painful