anonymous
  • anonymous
Need help with a discrete math problem.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Here is the problem.
1 Attachment
anonymous
  • anonymous
And here is what I have so far.
anonymous
  • anonymous
Except in the post above, I think we want the GCD not the GCF.

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anonymous
  • anonymous
sorry I can't help you I just start geometry
anonymous
  • anonymous
It's ok, just hope someone will be able to figure it out.
anonymous
  • anonymous
yes don't worry be patient ok body
anonymous
  • anonymous
@SithsAndGiggles
anonymous
  • anonymous
As far as I know, @DebbieG is on the right track. "Greatest common divisor" is the same as "greatest common factor."
anonymous
  • anonymous
I think Debbie just got it.
DebbieG
  • DebbieG
Reposting this here for inquiring minds that want to know... lol.... OK, wait... I was looking up some number theory/ GCD stuff. I found this: (a, b) = (a+kb, b) for any integer k HAH! So tell me if this works..... \(\Large (2^p\cdot 2^6-1,2^p\cdot 2^6+1)\) Now let k=-1, so we subtract the first one from the second one: \(\Large 2^p\cdot 2^6+1-(2^p\cdot 2^6-1)=2\) So now we have: \(\Large (2^p\cdot 2^6-1,2)\) Which..... pretty unquestionably.... is 1. Methinks? http://www.millersville.edu/~bikenaga/number-theory/gcd/gcd.pdf Bottom of pg 1 - top of pg 2.

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