anonymous
  • anonymous
Find the average rate of change of the distance from home between 1 and 3 hours after leaving home.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
inkyvoyd
  • inkyvoyd
\(=(y_t-y_0)/(t-t_0)\)
inkyvoyd
  • inkyvoyd
where \(t_0=1\) and t=3

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More answers

anonymous
  • anonymous
what is this part =(yt−y0)
inkyvoyd
  • inkyvoyd
y_t is y at 3 hours, y_0 is y at 1 hour
inkyvoyd
  • inkyvoyd
165 and 55, respectively I'm sorry I didn't offer you a clearer explanation, as I must go. You should get something around 110/2
anonymous
  • anonymous
but i need a mph
inkyvoyd
  • inkyvoyd
the units are in miles per hour silly; 55 mph
anonymous
  • anonymous
in the pack of my book it says 45mph im trying to figure out the work
anonymous
  • anonymous
Question #2 What is another word for rate of change in this situation?
anonymous
  • anonymous
Well, what's the rate of change of position? Distance is measured in miles, and time in hours. The rate of change of position is given by \[\frac{\Delta d}{\Delta t}=\frac{\text{miles}}{\text{hour}}\] What does that unit correspond to?
anonymous
  • anonymous
MPH
anonymous
  • anonymous
Right, a unit of ...
anonymous
  • anonymous
speed?
anonymous
  • anonymous
Yes, or velocity (depending on the context).
anonymous
  • anonymous
kk
anonymous
  • anonymous
Siths in the back of my Algebra 2 textbook it says 45 mph but how do i show the work
anonymous
  • anonymous
is there a formula
anonymous
  • anonymous
Yeah, @inkyvoyd has already shown it. It's basically \[\frac{\text{(distance at end of time interval)}-\text{(distance at start of time interval)}}{\text{(end time)}-\text{(start time)}}\]
anonymous
  • anonymous
nvm im not thinking today when i looked at the answer in the back of the book it was for problem #41 and i was looking for number 40. Thanks guys for both your help :D i really appreciate it.

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