LifeIsADangerousGame
  • LifeIsADangerousGame
Could someone please check this? Please? I really need this, its due tonight
Linear Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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LifeIsADangerousGame
  • LifeIsADangerousGame
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anonymous
  • anonymous
it looks ok so your good it think
anonymous
  • anonymous
might want ot double chekc number 3

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anonymous
  • anonymous
and number 4
anonymous
  • anonymous
absolute values can be broken up into 2 equations \[|x| = n\] is the equivalent of \[x=n \] and \[-(x)= n\]
LifeIsADangerousGame
  • LifeIsADangerousGame
Okay checking now
LifeIsADangerousGame
  • LifeIsADangerousGame
So for #3 I should put this as the answer? Y = 3 Y = -3 ?
LifeIsADangerousGame
  • LifeIsADangerousGame
Same thing for #4? S <= 3 S <= -3 ?
anonymous
  • anonymous
\[\frac{|3s-4|}{2} \le 2.5\] \[{|3s-4|} \le 5\] 2 inequalities \[3s-4 \le 5\] and \[-(3s-4)\le 5\] solve for both
LifeIsADangerousGame
  • LifeIsADangerousGame
First one is s <= 3 and the second one s => -1/3 Is that correct?
anonymous
  • anonymous
by the looks of it
LifeIsADangerousGame
  • LifeIsADangerousGame
AWesome c: Was #3 right?
LifeIsADangerousGame
  • LifeIsADangerousGame
@completeidiot
anonymous
  • anonymous
nope try substituting -3 into the equation
LifeIsADangerousGame
  • LifeIsADangerousGame
My revised answer was wrong or the original?
anonymous
  • anonymous
there's a revised answer?
LifeIsADangerousGame
  • LifeIsADangerousGame
Yes I said Y = 3 Y = -3
anonymous
  • anonymous
like i said, try plugging both those solutions in and see if it makes the equation true
anonymous
  • anonymous
i will say this, 10 is definitely not equal to 12
LifeIsADangerousGame
  • LifeIsADangerousGame
Well its not 3 and its not 2, is it a fraction?
LifeIsADangerousGame
  • LifeIsADangerousGame
wait is it 4 and -4?
anonymous
  • anonymous
SIGHHH stop guessing and just solve it...
LifeIsADangerousGame
  • LifeIsADangerousGame
I'm trying to solve it but nothing is working
anonymous
  • anonymous
5+ |2y+1|=12 subtract 5 from both sides |2y+1| = 7 now break up the absolute value into 2 equations 2y+1 = 7 & -(2y+1)=7 now solve for both y
LifeIsADangerousGame
  • LifeIsADangerousGame
2y + 1 = 7 -1 -1 2y = 6 divide 2 divide 2 y = 3 -(2y + 1) = 7 -2y - 1 = 7 + 1 +1 -2y = 8 divide by -2 divide by -2 y = -4 So the answer is y = 3 and y = -4?
LifeIsADangerousGame
  • LifeIsADangerousGame
@completeidiot
anonymous
  • anonymous
yes
LifeIsADangerousGame
  • LifeIsADangerousGame
AWesome c: You said everything else is correct?

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