anonymous
  • anonymous
(1/r) + (r/(2-r))=-7/4 How do you solve this??
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
to add fractions, their denominators must be the same. to do so we will force it by multiplying by the missing term(s). notice that were really just multiplying by one. \[\frac{ 1 }{ r } + \frac{ r }{ 2-r } = \frac{ 7 }{ 4 }\]\[\frac{ 1 }{ r }\times \frac{ 2-r }{ 2-r } + \frac{ r }{ 2-r } \times \frac{ r }{ r } = \frac{ 7 }{ 4 }\]\[\frac{ 2-r }{ r(2-r) } + \frac{ r^2 }{ r(2-r) } = \frac{ 7 }{ 4 }\]\[\frac{ 2-r + r^2 }{ r(2-r) } = \frac{ 7 }{ 4 }\]\[2-r+r^2 = \frac{ 7 }{ 4}\left( r(2-r) \right)\] and solve from here. probably best using the quadratic formula. let me know if you have follow-up questions ^_^
anonymous
  • anonymous
Wait May you type it using the equation generator I don't really understand what youutypes D;
anonymous
  • anonymous
i did use it. refreshing page might fix it

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anonymous
  • anonymous
mhm yea seems to not show up :\
anonymous
  • anonymous
\[x^2 = \pi\] do you see this as proper latex? are you blocking javascript with your browser?
anonymous
  • anonymous
hmhm yea that's what it seems
anonymous
  • anonymous
Would writing it out be better?

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