QueenV
  • QueenV
Buried treasure. Ahmed has half of a treasure map, which indicates that the treasure is buried in the desert 2x+6 paces from Castle Rock. Vanessa has the other half of the map. Her half indicates that to find the treasure, one must get to Castle Rock, walk x paces to the north, and then walk 2x+4 paces to the east. If they share their information, then they can find x and save a lot of digging. What is x? Pythagorean Quadratic problem. Can some one please tell me if I set this problem up correct? x^2+(2x+4) = (2x+6)^2
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
jim_thompson5910
  • jim_thompson5910
your set up is close, but it's incorrect unfortunately
jim_thompson5910
  • jim_thompson5910
it should be this x^2+(2x+4)^2 = (2x+6)^2 notice how the "(2x+4)" is squared
QueenV
  • QueenV
How about is the next step correct? x^2+4x^2+16x+16=4x^2+24x+36

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

jim_thompson5910
  • jim_thompson5910
yes it is, keep going
QueenV
  • QueenV
-4x^2 -4x^2 x^2+16x+16=24x+36 -24x -24x x^2-8x+36=36 -36 -36 x^2-8x-0+0
jim_thompson5910
  • jim_thompson5910
close
jim_thompson5910
  • jim_thompson5910
here's what I'm getting
jim_thompson5910
  • jim_thompson5910
x^2+(2x+4)^2 = (2x+6)^2 x^2+(2x+4)(2x+4) = (2x+6)(2x+6) x^2+2x(2x+4)+4(2x+4) = 2x(2x+6)+6(2x+6) x^2+4x^2+8x+8x+16 = 4x^2+12x+12x+36 5x^2+16x+16 = 4x^2+24x+36 5x^2+16x+16 - 4x^2-24x-36 = 0 x^2-8x-20 = 0
QueenV
  • QueenV
How did you get the 20
jim_thompson5910
  • jim_thompson5910
16 - 36 = -20
jim_thompson5910
  • jim_thompson5910
on the left side, you had 16, but it somehow changed to 36
QueenV
  • QueenV
Did I skip steps/
QueenV
  • QueenV
Ok I got you. I see. x^2-8x-20 so now I need two factors of 20 that add up to 8?
jim_thompson5910
  • jim_thompson5910
-20 and -8, but yes
QueenV
  • QueenV
5*4 =20, 5+4=9, 2*10=20, 2+10 =12, 10+10=20 I have no idea
jim_thompson5910
  • jim_thompson5910
how about -10 and 2
jim_thompson5910
  • jim_thompson5910
-10 + 2 = -8 -10 * 2 = -20
QueenV
  • QueenV
ok, wasn't thinking of the negatives. (x-10)(x+8)?
jim_thompson5910
  • jim_thompson5910
good
jim_thompson5910
  • jim_thompson5910
oh sry misread
jim_thompson5910
  • jim_thompson5910
it should be (x-10)(x+2)
QueenV
  • QueenV
(x-10)(x+2) that is what I meant sorry
jim_thompson5910
  • jim_thompson5910
so if x^2-8x-20 = 0 then (x-10)(x+2) = 0
jim_thompson5910
  • jim_thompson5910
and if (x-10)(x+2) = 0 then by the zero product property x-10 = 0 or x+2 = 0
QueenV
  • QueenV
that is far as we can go?
jim_thompson5910
  • jim_thompson5910
no we can go a few steps further
jim_thompson5910
  • jim_thompson5910
we need to fully isolate x
QueenV
  • QueenV
Ok, we haven't got that far yet, but will you show me?
jim_thompson5910
  • jim_thompson5910
if x-10 = 0, then x = ???
QueenV
  • QueenV
0
jim_thompson5910
  • jim_thompson5910
no
jim_thompson5910
  • jim_thompson5910
if x-10 = 0, then x = ???
QueenV
  • QueenV
I0
jim_thompson5910
  • jim_thompson5910
better
jim_thompson5910
  • jim_thompson5910
if x+2 = 0, then x = ???
QueenV
  • QueenV
-2
jim_thompson5910
  • jim_thompson5910
so this means we have these 4 steps at the end x^2-8x-20 = 0 (x-10)(x+2) = 0 x-10 = 0 or x+2 = 0 x = 10 or x = -2
jim_thompson5910
  • jim_thompson5910
but remember that x is a distance or length you CANNOT have negative distances or lengths, so x = -2 makes no sense in the real world
jim_thompson5910
  • jim_thompson5910
so that means we must toss x = -2 therefore, the only solution is x = 10
QueenV
  • QueenV
okay, thank you very much for your patience. May the Lord God Bless you, you have helped me greatly.
jim_thompson5910
  • jim_thompson5910
you're welcome, glad to be of help

Looking for something else?

Not the answer you are looking for? Search for more explanations.