anonymous
  • anonymous
4x^2-35x+49
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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tkhunny
  • tkhunny
That's a lovely expression. What is to be done. By the way, I am immediately tantalized by the fact that the first and last terms are perfect squares. I wonder if that will help us?
anonymous
  • anonymous
I have no clue how to even start solving this problem. Do you know how? Can you show me the steps?
tkhunny
  • tkhunny
Well, so far we have only an expression. There are NO instructions?

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anonymous
  • anonymous
Nope. There isn't any instructions
tkhunny
  • tkhunny
Wow, that's really sad. Why in the name of reason are you given nothing? Utterly senseless. Anyway, perhaps we are to factor it? 4x^2-35x+49 Like I said up top, since both the first and last terms are perfect squares, I'm tempted just to give it a shot without any further effort. 4x^2 = (2x)^2 49 = (7)^2 Does this work? (2x-7)^2 Multiply that out and see if we get back where we started/.
anonymous
  • anonymous
I am so sorry. I Honestly have no idea what I'm doing...
UnkleRhaukus
  • UnkleRhaukus
\[ax^2+bx+c=0\] \[x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] \[(x-x_1)(x-x_2)=0\]
tkhunny
  • tkhunny
Have you ever multiplied to binomials? (a+2)(a-3) = a^2 +2a - 3a - 6 = a^2 -a -6 Something like that?
anonymous
  • anonymous
Nope, I have not
tkhunny
  • tkhunny
Fair enough. Then you have no immediate capacity to solve what we have imagined this problem to be. If this is a placement exam, the course where this material is covered may be the right course for you. If you are already in this class, you are in for a very unfortunate semester. A quick chat with your academic adviser may be the best course of action. Good luck.

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