Math2400
  • Math2400
could someone tell me if these answers are correct? I missed my teachers lesson<< 9. D 10. a) .037 m/s b) not enough info **Postin pic
Physics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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Math2400
  • Math2400
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Math2400
  • Math2400
or is a and b the same answer? since speed is basically velocity...
theEric
  • theEric
Hi! I agree with your answer for 9!

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Math2400
  • Math2400
cool and 10? << lol I think i may have messed up
theEric
  • theEric
For that one, we look at \(\bar v=\dfrac{\Delta x}{\Delta t}\) for velocity. And you are right, we can't know what the average speed is!
Math2400
  • Math2400
cool so both answers r correct then..?
Math2400
  • Math2400
wait i think i did something wrong! i divided by the wrong number i think lol
Math2400
  • Math2400
is it .012 m/s?
theEric
  • theEric
I got a different answer for 10a! \(\bar v=\dfrac{x_2-x_1}{t_2-t_1}=\dfrac{8.5\ [m]-2.7\ [m]}{6.0\ [s]-(-3.0\ [s])}\\~\\\qquad\qquad=\dfrac{8.5\ [m]-2.7\ [m]}{6.0\ [s]+3.0\ [s]}=\dfrac{5.8\ [m]}{9\ [s]}=.6\bar4\ [m/s]\\~\\\qquad\qquad\approx.64\ [m/s]\)
Math2400
  • Math2400
ohhh i see what you did there! i added instead but i understand now. Thank u so much!! But may i ask, what info and equation would i use if to find the average speed then?
Math2400
  • Math2400
cuz i think i may have used the average speed formula to get my answer but it's wrong lol
theEric
  • theEric
Oh! Haha, with average speed, you don't want the change in position (\(\Delta x\)), but the change in the distance traveled. The distance traveled will be positive with increasing time, because it is not a vector and so direction is not considered (so no negative signs!). To find average speed, you need the change in distance, rather than displacement (change in position).
theEric
  • theEric
Which formula did you use? If I recognize it, I'll let you know what it is!

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