anonymous
  • anonymous
Let n be an integer. Prove than n^2 is greater than or equal to 0. Consider the three cases: n>0, n=0, and n<0.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
anybody?
nincompoop
  • nincompoop
let me see you work it out
anonymous
  • anonymous
lol @nincompoop

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anonymous
  • anonymous
i just dont know if im actually proving it or if im doing a circular proof
nincompoop
  • nincompoop
try proof
anonymous
  • anonymous
alright hang on it will take a second to type it
anonymous
  • anonymous
Case 1: suppose that n<0 -n<=0 n>=0 (-n)*n<=0*(-n) -n^2<=0 n^2>=0
anonymous
  • anonymous
you here still?
nincompoop
  • nincompoop
yeh. continue

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