anonymous
  • anonymous
momentum and collision
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Is it an elastic collision or an inelastic collision ??
anonymous
  • anonymous
it doesn't state that
anonymous
  • anonymous
So the question cant be answered because coefficient of restitution should be known to find the type of collision

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
it says head on collision
anonymous
  • anonymous
Head on means the axis on collision are at zero degree to each other. U can assume it to be elastic as far i feel like.
anonymous
  • anonymous
alright lets solve it that way
anonymous
  • anonymous
Hey check the question . North n East are at 90 degree. Its gonna be an in elastic collision then
anonymous
  • anonymous
sorry it is west and east i didnt notice at the directions while wiritng
anonymous
  • anonymous
Then assume it to be elastic n single axis collision.
anonymous
  • anonymous
ok so how do we solve it
Jack1
  • Jack1
|dw:1378719031169:dw|
Jack1
  • Jack1
p = momentum m = mass v = velocity p = mv so p truck (before collision) = ? and p car (before collision) = ?
anonymous
  • anonymous
|dw:1378719256892:dw|
anonymous
  • anonymous
M1U1 + M2U2 = (M1+M2)V M1, M2, U1,U2 are given in question. Substitute to find V
Jack1
  • Jack1
cool so p before = p after if we're assuming an elastic collision (conservation of momentum) does it state whether the truch and car stick together?
anonymous
  • anonymous
That is not written
anonymous
  • anonymous
hey guys in the textbook ot is conservation of momentum i have no idea about rest part
anonymous
  • anonymous
I wrote the conservation of momentum formula above
Jack1
  • Jack1
cool dude, so assume a merging of the mass after collision and use @frnd 's formula above: m1 u1 + m2 ... etc solve for v u is initial speed of each respectively
anonymous
  • anonymous
whats u textbook has p total = p1 + p2 + p3 + ....+pn
Jack1
  • Jack1
?
Jack1
  • Jack1
p = mv so all textbooks dealing with conservation of momentum
anonymous
  • anonymous
whats u in the formula frnd provided ? textbook has p_total = p_1 + p_2 + p_3 + ....+p_n...p is vector
Jack1
  • Jack1
ignore the textbook then, this question is alot simpler so use what's easy the classic equation for conservation of momentum in an elastic collision is M1U1 + M2U2 = (M1+M2)V M1 = mass of truck, M2 = mass of car, U1 = speed of truck U2 = speed of car vector analysis only comes into this equation to the extent that as they're travelling in exactly opposite directions, make one of the directions the reference point, ie the truck, and therefore make the other direction negative, therefore speed of car = -150 mph = -67.1 m/s Substitute to find V
Jack1
  • Jack1
|dw:1378720567315:dw|
anonymous
  • anonymous
181050=4500v v=40.233
anonymous
  • anonymous
i think v has units too right @Jack1
Jack1
  • Jack1
sorry dude, did u remember to use negative 67.056 as your value for u2? and v is in m/s, velocity has both magnitude and direction so remember to give it the appropriate direction based on positive or negative answer
anonymous
  • anonymous
oops
Jack1
  • Jack1
|dw:1378721164974:dw|
anonymous
  • anonymous
v = -4.5 some units
Jack1
  • Jack1
yep, i got -4.74, rounded up to sig figs is -4.7 meters/second , and as its negative we know it's moving west (as east was our reference direction) so v= 4.7m/s west after collision
anonymous
  • anonymous
yep....so wait what did we just find @Jack1
Jack1
  • Jack1
the car and the truck crash together they have different masses, speeds and directions before the crash they merge together because of the crash the new joined mass has a velocity of 4.7m/s west after the crash you can put this in terms of momentum if you wish (mass of wreck = 4500...assuming kgs?) momentum of wreck = 20, 117 west
anonymous
  • anonymous
last confusion where did you get 20, 117 from
Jack1
  • Jack1
momentum units kg . m/s (assuming your weights are in kgs?)
anonymous
  • anonymous
ya mass is in kg
Jack1
  • Jack1
21,117 by not rounding if you go 4.7*4500 = 21,150 but use: a*b + c*d = (a+c)V, a = 3000, c = 1500, b = (60*0.44704), d = (-150*0.44704) note: 1 mph = 0.44704 m/s then gives you momentum of 20,116.8 kg . m/s then rounding = 20,117
anonymous
  • anonymous
ty so much helped a lot
anonymous
  • anonymous
waht r the units again
Jack1
  • Jack1
all good dude, always welcome hey, sing out if you need clarification on anything if not, slaters ;)
anonymous
  • anonymous
lol, this stuff is so easy! [:
Jack1
  • Jack1
of momentum: kg . m/s of velocity: meters/second of mass: kg
anonymous
  • anonymous
its fine dude, we r frnds @Jack1 thats why she was bragging it
Jack1
  • Jack1
ah, nvmd, my bad ;{
anonymous
  • anonymous
u good ... thx for explaining stuff
Jack1
  • Jack1
yw, cya

Looking for something else?

Not the answer you are looking for? Search for more explanations.