Did I solve this correctly? So the problem is 3(2x+7)>36. So I distributed the 3. To get 6x+ 21>36. I took away the 36 to get - 15. So I ended up with 6x=15 and when I divided it, I got -2.5. I don't think I solved the problem right

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It would be easier if you just subtract 21.

instead of distributing 3, you can divide both sides of the equation by 3

I would have done this.
\(3(2x+7)>36\)
\(2x+7>12\)
\(2x>5\)
\(x>\dfrac{5}{2}\)

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