anonymous
  • anonymous
Calculating Range of a function
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
\[f(x) = \sqrt{x-1}\]
anonymous
  • anonymous
I can do the domain but not the range
anonymous
  • anonymous
Help please @Luigi0210

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Luigi0210
  • Luigi0210
I gtg so.. @austinL
austinL
  • austinL
Graph the function and look at the values that it takes of y.
anonymous
  • anonymous
I did that, but the problem said to solve for it first
anonymous
  • anonymous
??? I can solve for domain but not range
anonymous
  • anonymous
Find the derivative of the following via implicit differentiation: d/dx(f(x)) = d/dx(x-1---(-(-sqrt(x)))) Rewrite the expression: d/dx(f(x)) = d/dx(f(x)): d/dx(f(x)) = d/dx(-sqrt(x)+x) The derivative of f(x) is f'(x): f'(x) = d/dx(-sqrt(x)+x) Differentiate the sum term by term and factor out constants: f'(x) = d/dx(x)-d/dx(sqrt(x)) Use the power rule, d/dx(x^n) = n x^(n-1), where n = 1/2: d/dx(sqrt(x)) = d/dx(x^(1/2)) = x^(-1/2)/2: f'(x) = d/dx(x)-1/(2 sqrt(x)) The derivative of x is 1: f'(x) = -1/(2 sqrt(x))+1 Expand the left hand side: Answer: | | f'(x) = 1-1/(2 sqrt(x))
anonymous
  • anonymous
I don't know derivatives yet. sorry
anonymous
  • anonymous
Oh =(
anonymous
  • anonymous
I'll just close the question

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