Why in this case does lim t -> 0 [8t/sin(8t)] =1 ?
lim t ->0 [sin(3t)/3t] * lim t -> 0 [8t/sin(8t)]
BUT in this case
lim x -> 0 x/sin(7x) we have to invert it?

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So even as the reciprocal the limit = 1?

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