anonymous
  • anonymous
What is the mage of point D in figure ABCD for a dilation with a center of (0,0) and a scale factor of 2?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@jim_thompson5910
jim_thompson5910
  • jim_thompson5910
the figure is missing
anonymous
  • anonymous

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

jim_thompson5910
  • jim_thompson5910
what is point D?
anonymous
  • anonymous
-2?
jim_thompson5910
  • jim_thompson5910
as an ordered pair, where is point D?
jim_thompson5910
  • jim_thompson5910
ie what are the coordinates of it? or its location?
anonymous
  • anonymous
I don't know... that's why I'm asking for help.
jim_thompson5910
  • jim_thompson5910
well you start at (0,0), which is the origin
jim_thompson5910
  • jim_thompson5910
then you go to the left 1 unit then you go up 4 units to get to the point ________
anonymous
  • anonymous
D
anonymous
  • anonymous
wait, then you go left 1 after what?
jim_thompson5910
  • jim_thompson5910
yes but where is point D ex: if you went to the right 1 and up 3, then you would be at the point (1,3)
anonymous
  • anonymous
okay then I scale it by the factor of 2?
jim_thompson5910
  • jim_thompson5910
yes but first tell me where point D is
jim_thompson5910
  • jim_thompson5910
what is the (x,y) form of this point
anonymous
  • anonymous
-3,4?
jim_thompson5910
  • jim_thompson5910
close, but it's (-1, 4) you go over to the left 1, then up 4
anonymous
  • anonymous
no.. nevermind.
jim_thompson5910
  • jim_thompson5910
D is the point (-1,4)
anonymous
  • anonymous
yeah.. I was looking at point A for one of the coordinates
jim_thompson5910
  • jim_thompson5910
when you apply the scale factor of 2, you double each coordinate
anonymous
  • anonymous
Okay it was what I though it was.
anonymous
  • anonymous
Could you check my answer on another question?
jim_thompson5910
  • jim_thompson5910
sure what do you need
anonymous
  • anonymous
What is the perimeter of the rectangle with vertices F(-6,-10), G(10,2), H(7,6), and I(-9,-6)? My answer:
anonymous
  • anonymous
2(w + h) 2(-6 + -10) = -32 2(10 + 2) = 24 2(7 + 6) = 26 (-9 + -6) = -30
jim_thompson5910
  • jim_thompson5910
do you remember the distance formula?
anonymous
  • anonymous
distance formula for what?
anonymous
  • anonymous
I think so..
jim_thompson5910
  • jim_thompson5910
for finding the distance between two points
jim_thompson5910
  • jim_thompson5910
for instance, what is the distance from point F to point G?
anonymous
  • anonymous
I don't know... ?
jim_thompson5910
  • jim_thompson5910
use the distance formula \[\large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}\] to find out
anonymous
  • anonymous
I don't feel like I'm inputting it correctly.
jim_thompson5910
  • jim_thompson5910
show me what you got so far
anonymous
  • anonymous
do I use just one coordinate pair at a time?
jim_thompson5910
  • jim_thompson5910
you use them both
jim_thompson5910
  • jim_thompson5910
(x1,y1) is the first point (x2,y2) is the second point
anonymous
  • anonymous
yes.. but how can that work when there are 4 pairs of coordinates?
jim_thompson5910
  • jim_thompson5910
you do them a pair at a time
jim_thompson5910
  • jim_thompson5910
so if you want to find the distance from F to G, you only focus on those two points
anonymous
  • anonymous
can you input an example? I don't think you're understanding my question
jim_thompson5910
  • jim_thompson5910
Let's make point F the first point so that means F(-6,-10) = (x1,y1) which means x1 = -6 y1 = -10 see how I'm getting this?
anonymous
  • anonymous
d = sqrt(-6-10)^2 + (-10-2)^2?
jim_thompson5910
  • jim_thompson5910
so far, so good
jim_thompson5910
  • jim_thompson5910
now simplify/evaluate
anonymous
  • anonymous
Okay..can you check
jim_thompson5910
  • jim_thompson5910
what did you get
anonymous
  • anonymous
20
jim_thompson5910
  • jim_thompson5910
good
jim_thompson5910
  • jim_thompson5910
so that is the length of one side luckily the opposite side is also 20 because this a rectangle (opposite sides of a rectangle are equal)
anonymous
  • anonymous
okay.. now the same thing for the other coordinates?
jim_thompson5910
  • jim_thompson5910
so you can think of it as the length of 20 units
jim_thompson5910
  • jim_thompson5910
yes you need to find the width now
anonymous
  • anonymous
ok one sec
anonymous
  • anonymous
d = sqrt(7-(-9)^2 + (6-(-6))^2 look okay for the first step?
jim_thompson5910
  • jim_thompson5910
yes it does, keep going
anonymous
  • anonymous
d = sqrt(x2-x1)^2 + (y2-y1)^2 d = sqrt(7-(-9)^2 + (6-(-6))^2 d = sqrt(16)^2 + (12)^2 d = sqrt(256)^2 + (144)^2 d = sqrt(65,536)+(20,736) d = sqrt(86,272) d = 293.720956 rounded: 293.7
jim_thompson5910
  • jim_thompson5910
you're doing great until you hit this line d = sqrt(65,536)+(20,736)
jim_thompson5910
  • jim_thompson5910
it should be this d = sqrt( 16^2 + 12^2 ) d = sqrt( 256 + 144 ) d = sqrt( 400 ) d = 20
jim_thompson5910
  • jim_thompson5910
so the distance from point H to point I is 20 units
anonymous
  • anonymous
ohhh hahaha whoops okay so from H to I is 20 and f to g is 20?
jim_thompson5910
  • jim_thompson5910
correct on both
jim_thompson5910
  • jim_thompson5910
you just need two more sides once you have the length of all 4 sides, you can add them up to get the perimeter
anonymous
  • anonymous
How do I get the other two?
jim_thompson5910
  • jim_thompson5910
find the distance from G to H
anonymous
  • anonymous
Why not F to I?
jim_thompson5910
  • jim_thompson5910
that's another side length we'll get to
anonymous
  • anonymous
d = sqrt(x2-x1)^2 + (y2-y1)^2 d = sqrt(10-7)^2 + (2-6)^2 d = sqrt(3)^2 + (-4)^2 d = sqrt(9) + (16) d= sqrt(25) d = 5 The distance from G to H is 5 units.
jim_thompson5910
  • jim_thompson5910
good
jim_thompson5910
  • jim_thompson5910
how about from F to I
anonymous
  • anonymous
d = sqrt(x2-x1)^2 + (y2-y1)^2 d = sqrt(-6-(-9))^2 + (-10-(-6))^2 d = sqrt(3)^2 + (-4)^2 d = sqrt(9) + (16) d = sqrt(25) d = 5 The distance from F to I is 5 units.
jim_thompson5910
  • jim_thompson5910
very good
jim_thompson5910
  • jim_thompson5910
now add up the 4 sides to get the perimeter
anonymous
  • anonymous
the perimeter is 50 units
jim_thompson5910
  • jim_thompson5910
perfect
anonymous
  • anonymous
thank you!!
jim_thompson5910
  • jim_thompson5910
you're welcome

Looking for something else?

Not the answer you are looking for? Search for more explanations.