anonymous
  • anonymous
problem ...need to be solved with real theories
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[-20=20\] \[16-36=25-45\] \[4^{2}-4\times{9 } =5^{2}-5\times{ 9 }\] \[4^{2}-2\times4\times\frac{9 }{ 2 }=5^{2}-2\times5\frac{ 9 }{ 2}\] \[4^{2}-2\times4\times\frac{9 }{ 2 }+\left( \frac{ 9 }{ 2 } \right)^{2}=5^{2}-2\times5\frac{ 9 }{ 2}+\left( \frac{ 9 }{ 2 } \right)^{2}\] \[\left( 4-\frac{ 9 }{ 2 } \right)^{2}=\left( 5-\frac{ 9}{ 2 } \right)^{2}\] \[\sqrt{\left( 4-\frac{ 9 }{ 2 } \right)^{2}}=\sqrt{\left( 5-\frac{ 9}{ 2 } \right)^{2}}\] \[4-\frac{ 9 }{ 2 }=5-\frac{ 9 }{ 2 }\] |dw:1378759825635:dw|
anonymous
  • anonymous
how can I edit ? −20=-20 m sory it meant like this both negative
anonymous
  • anonymous
what level math is this?

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anonymous
  • anonymous
the high level I mean numbers on R
anonymous
  • anonymous
hmm... what definition of real number you use? Dedekind partitions maybe?
anonymous
  • anonymous
a made up confusion I am not sure the wrong step . but is 4 double of -2,2 in all condition accept geyometrical calculations when we take off the root square with absolute value ?
anonymous
  • anonymous
square root taking is like finding side of square who's diagonal is equal to the number under root sign
anonymous
  • anonymous
but still the result is not equal even if both are negative
anonymous
  • anonymous
length can never be negative
anonymous
  • anonymous
I think that's what is ment by geometrical calculations
anonymous
  • anonymous
it appears that: \[\pm (4 - \frac{ 9 }{ 2 }) = ∓(5-\frac{ 9 }{ 2 })\]
anonymous
  • anonymous
yes exactelly but why ? mean wich step is wrong and how ..
hartnn
  • hartnn
\(\sqrt{x^2}= |x|\) actually
hartnn
  • hartnn
so, if x is negative, as is the case for 4-9/2 |x| will be -x = - (4-9/2) = 1/2 for 5-9/2, x is positive so |x| =x so, 5-9/2 = 1/2
hartnn
  • hartnn
got this ?
hartnn
  • hartnn
because answer of square root can never be negative while dealing with real numbers
anonymous
  • anonymous
it's been a long time for me since i studied those. one more thing i there like a theorical proof ? texts ... and thanks seems obviously right
hartnn
  • hartnn
theoritical proof...if i find one i will attach...

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