anonymous
  • anonymous
please help
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[\sqrt{121a^2b^2}\]
anonymous
  • anonymous
\[\sqrt{abc} = \sqrt{a} \times \sqrt{b} \times \sqrt{c}\]
anonymous
  • anonymous
@jdoe0001

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jdoe0001
  • jdoe0001
\(\bf\sqrt{121a^2b^2}\\ --------\\ 121 = 11^2\\ --------\\ \sqrt{121a^2b^2}\implies \sqrt{11^2a^2b^2}\)
jdoe0001
  • jdoe0001
so, that leaves you with?
jdoe0001
  • jdoe0001
|dw:1378841502123:dw|
anonymous
  • anonymous
I know the 11 is the answer but how do the letters
jdoe0001
  • jdoe0001
the letters come out as well why? because their exponent, just like for 11, matches the radical root
anonymous
  • anonymous
okay please show me how to do it
jdoe0001
  • jdoe0001
the root is 2, squared root, so, anything with an exponent matching "2", will come out
anonymous
  • anonymous
so would it just be 11ab
jdoe0001
  • jdoe0001
yeap

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