anonymous
  • anonymous
Attachment below: geometry
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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anonymous
  • anonymous
anonymous
  • anonymous
@jim_thompson5910
jim_thompson5910
  • jim_thompson5910
first we need to find the length of AC

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jim_thompson5910
  • jim_thompson5910
so use the distance formula for this
anonymous
  • anonymous
what numbers do we input though?
jim_thompson5910
  • jim_thompson5910
the coordinates of A and C
anonymous
  • anonymous
is it 7 or 6 for A?
anonymous
  • anonymous
C is 4 or 4.something?
jim_thompson5910
  • jim_thompson5910
what is the ordered pair for point A
anonymous
  • anonymous
6, 4?
jim_thompson5910
  • jim_thompson5910
you sure?
jim_thompson5910
  • jim_thompson5910
again I'm asking for point A
anonymous
  • anonymous
No, I'm not.. I'm not sure what point A is at.
jim_thompson5910
  • jim_thompson5910
you start at the origin (0,0) this is where the x and y axis cross
jim_thompson5910
  • jim_thompson5910
now how many spaces must you go to the left to get to point A? how many spaces do you go up or down?
anonymous
  • anonymous
Yes.. I understand how to find it but I'm not sure if it's 6 or 7.
anonymous
  • anonymous
-7
jim_thompson5910
  • jim_thompson5910
it's 6 units to the left so A is the point (-6, 0)
anonymous
  • anonymous
yeah.. I forgot the negative sign. so -6,
jim_thompson5910
  • jim_thompson5910
the y coordinate is 0 since you don't go up or down and you stay on the x axis
jim_thompson5910
  • jim_thompson5910
what is point C
anonymous
  • anonymous
don't we have to find AB, BC, and AC?
jim_thompson5910
  • jim_thompson5910
no all we need right now is AC
anonymous
  • anonymous
why are we doing one point at a time? for the form.?
anonymous
  • anonymous
ohhh
jim_thompson5910
  • jim_thompson5910
we need AC because we're trying to prove that some new line segment is parallel to AC and it's half the length so we need the length of AC first
jim_thompson5910
  • jim_thompson5910
to find the length of AC, we use the distance formula but to do that, we need the points A and C (the x,y form of both points)
anonymous
  • anonymous
okay.. but how do I figure out C? considering it's not an even number
jim_thompson5910
  • jim_thompson5910
C is the point (0,-4) you start at (0,0) then go down 4 ticks or units to land on C
jim_thompson5910
  • jim_thompson5910
I honestly don't know what the -6.67 is referring to
anonymous
  • anonymous
so it's -6,-4?
jim_thompson5910
  • jim_thompson5910
no (0,-4) notice how you don't go left/right from the origin to get to C
anonymous
  • anonymous
no, I mean for AC....
jim_thompson5910
  • jim_thompson5910
oh AC is the distance from A to C
jim_thompson5910
  • jim_thompson5910
when I say AC, I really mean "find the length of segment AC"
anonymous
  • anonymous
Now, I'm lost. I just meant the coordinates...
jim_thompson5910
  • jim_thompson5910
we know that A is the point (-6,0) C is the point (0,-4) the distance from A to C is ????
anonymous
  • anonymous
Should I use a formula or just subtract?
jim_thompson5910
  • jim_thompson5910
I'd use the formula so you get more practice using it
anonymous
  • anonymous
one sec
jim_thompson5910
  • jim_thompson5910
ok
anonymous
  • anonymous
d = sqrt(-6, 0)^2 + (0 - (-4))^2??
jim_thompson5910
  • jim_thompson5910
i think you meant to say -6 - 0 instead of -6, 0
jim_thompson5910
  • jim_thompson5910
if so, then you are correct so far
anonymous
  • anonymous
d = sqrt(x2-x1)^2+(y2-y1)^2 d = sqrt(-6 - 0)^2 + (0 - (-4))^2 d = sqrt(-6)^2 + (4)^2 d = sqrt(36) + (16) d = sqrt(52) d = 7.2
jim_thompson5910
  • jim_thompson5910
good
jim_thompson5910
  • jim_thompson5910
now you must find the midpoints of AB and BC
anonymous
  • anonymous
Do I do AB now?
jim_thompson5910
  • jim_thompson5910
yes you need the midpoint of AB you do NOT need to find the distance from A to B
anonymous
  • anonymous
how do I do this?
jim_thompson5910
  • jim_thompson5910
use the midpoint formula http://www.purplemath.com/modules/midpoint.htm the link above explains what the formula is and how it works
anonymous
  • anonymous
Yeah but what numbers do I put in? I actually remember this formula
jim_thompson5910
  • jim_thompson5910
the coordinates of A and B
anonymous
  • anonymous
0,4 ?
jim_thompson5910
  • jim_thompson5910
that's point B
jim_thompson5910
  • jim_thompson5910
A(-6,0) B(0,4)
jim_thompson5910
  • jim_thompson5910
now use the midpoint formula
anonymous
  • anonymous
-6 + 0/2, 0 + 4/2?
jim_thompson5910
  • jim_thompson5910
keep going
anonymous
  • anonymous
-3, 2
jim_thompson5910
  • jim_thompson5910
good, that's the midpoint of AB let's call this point M
jim_thompson5910
  • jim_thompson5910
what is the midpoint of BC?
anonymous
  • anonymous
is it 0,4 and 0,4?
anonymous
  • anonymous
not the midpoint
jim_thompson5910
  • jim_thompson5910
B(0,4) C(0,-4) midpoint is ????
anonymous
  • anonymous
2, -2?
jim_thompson5910
  • jim_thompson5910
no
anonymous
  • anonymous
I must be doing something wrong
jim_thompson5910
  • jim_thompson5910
the x coordinates of the two points are 0 and 0 add them, divide by 2 (0+0)/2 0/2 0 so the x coordinate of the midpoint is 0
jim_thompson5910
  • jim_thompson5910
what is the y coordinate of the midpoint ?
anonymous
  • anonymous
I see what I did wrong. It's 0, -2
jim_thompson5910
  • jim_thompson5910
no it's not
jim_thompson5910
  • jim_thompson5910
the y coordinates are 4 and -4 they add to 0 cut this in half to get 0
jim_thompson5910
  • jim_thompson5910
so the midpoint is (0,0)
jim_thompson5910
  • jim_thompson5910
so let the point N be the midpoint of BC this means N is the point (0,0)
jim_thompson5910
  • jim_thompson5910
you have two new points: M(-3,2) and N(0,0) you need to do two things now a) find the slope of MN b) find the length of MN
anonymous
  • anonymous
one sec
jim_thompson5910
  • jim_thompson5910
ok
anonymous
  • anonymous
My computer froze and I lost all my answers on the test. I'll come back to this question after.
anonymous
  • anonymous
Hey, could we work from a certain step?
jim_thompson5910
  • jim_thompson5910
I'm sorry, I cannot help you on tests since it's something you should do on your own.
anonymous
  • anonymous
It's not a test... I was talking about something else. Not what I was consulting with you with.
anonymous
  • anonymous
This is for practice.
jim_thompson5910
  • jim_thompson5910
alright
anonymous
  • anonymous
How do we find the slope? and the test I was doing was for English
jim_thompson5910
  • jim_thompson5910
what are the two points?
anonymous
  • anonymous
M(-3,2) and N(0,0)?
jim_thompson5910
  • jim_thompson5910
use the slope formula to get this m = (y2-y1)/(x2-x1) m = (0-2)/(0-(-3)) m = (0-2)/(0+3) m = -2/3
anonymous
  • anonymous
so that's for one side or both?
jim_thompson5910
  • jim_thompson5910
I'm not sure what you mean
jim_thompson5910
  • jim_thompson5910
is this for the same problem? or a different problem?
anonymous
  • anonymous
Same. There was two points so I was wondering.
jim_thompson5910
  • jim_thompson5910
oh that's right you needed to find the slope of MN
anonymous
  • anonymous
Now I'm confused hahaha
jim_thompson5910
  • jim_thompson5910
and yes you need two points to find the slope one is not enough
anonymous
  • anonymous
can we start from when we found N?
jim_thompson5910
  • jim_thompson5910
yeah it doesn't help that this happened nearly 5 hours ago
jim_thompson5910
  • jim_thompson5910
you saw how to get M and N right?
anonymous
  • anonymous
right, I don't have N written down. Can we do that over? It was 0, 4 right?
anonymous
  • anonymous
and then go from there...
jim_thompson5910
  • jim_thompson5910
to find N, we need to find the midpoint of BC
jim_thompson5910
  • jim_thompson5910
B(0,4) C(0,-4)
anonymous
  • anonymous
I think I'm inputting it wrong.. I got the right answer now I'm getting it wrong
jim_thompson5910
  • jim_thompson5910
remember the midpoint formula?
anonymous
  • anonymous
Yep
jim_thompson5910
  • jim_thompson5910
so what is the midpoint of BC
anonymous
  • anonymous
I'm getting 0, -2 but isn't it 0,0?
jim_thompson5910
  • jim_thompson5910
it should be (0,0) yes
jim_thompson5910
  • jim_thompson5910
4 + (-4) = 0 divide that by 2 to get 0/2 = 0 so that's why the y coordinate of N is 0
anonymous
  • anonymous
oh, I inputted wrong. Could you show the input?
jim_thompson5910
  • jim_thompson5910
to get the midpoint?
anonymous
  • anonymous
I'm inputting the numbers wrong for the midpoint formula, yes
jim_thompson5910
  • jim_thompson5910
x coordinate of midpoint: (x1+x2)/2 x coordinate of midpoint: (0+0)/2 x coordinate of midpoint: (0)/2 x coordinate of midpoint: 0 ------------------------------------------------------- y coordinate of midpoint: (x1+x2)/2 y coordinate of midpoint: (4 + (-4))/2 y coordinate of midpoint: (0)/2 y coordinate of midpoint: 0
jim_thompson5910
  • jim_thompson5910
Therefore the midpoint of BC is N(0,0)
anonymous
  • anonymous
Okay... I got it now.
jim_thompson5910
  • jim_thompson5910
ok great
anonymous
  • anonymous
So now what do we do? Find the slope?
jim_thompson5910
  • jim_thompson5910
yes but we did that above
jim_thompson5910
  • jim_thompson5910
I showed the steps for that earlier
anonymous
  • anonymous
yeah.. but it was confusing. Do we just use that formula for both points?
jim_thompson5910
  • jim_thompson5910
I used the slope formula where are you stuck on those steps?
anonymous
  • anonymous
So the overall answer is -2, 3?
anonymous
  • anonymous
No I got that part.
jim_thompson5910
  • jim_thompson5910
the slope of MN is -2/3
anonymous
  • anonymous
Alright, I understand. Thanks.
jim_thompson5910
  • jim_thompson5910
that's great you then use the slope formula to find the slope of AC and compare the two slopes
jim_thompson5910
  • jim_thompson5910
also you'll need to find the length of MN
anonymous
  • anonymous
So find the slope of AC and then the length of MN? Is there anything else?
jim_thompson5910
  • jim_thompson5910
not that I can think of you should find that the slope of AC is also -2/3 this will help prove that AC and MN are parallel
jim_thompson5910
  • jim_thompson5910
also, you should find that MN is half as long as AC so that proves the second part
anonymous
  • anonymous
how do I find the slope for AC? The answer was 7.2
jim_thompson5910
  • jim_thompson5910
basically you subtract the y coordinates and subtract the x coordinates after all that you divide the two differences (y difference over x difference)
jim_thompson5910
  • jim_thompson5910
that's how you find the slope
anonymous
  • anonymous
How should I find the length of MN though?
jim_thompson5910
  • jim_thompson5910
by using the distance formula
jim_thompson5910
  • jim_thompson5910
find the distance from M to N
anonymous
  • anonymous
by using the distance formula? so after the last step we did, what would I do?
anonymous
  • anonymous
slope AC?
jim_thompson5910
  • jim_thompson5910
what are the points for A and C
anonymous
  • anonymous
I only have the distance
jim_thompson5910
  • jim_thompson5910
but you have the coordinates for points A and C
anonymous
  • anonymous
-6,0 and 0, -4?
jim_thompson5910
  • jim_thompson5910
good, so use the slope formula to get m = (y2-y1)/(x2-x1) m = (-4-0)/(0-(-6)) m = (-4-0)/(0+6) m = (-4)/6 m = -2/3
jim_thompson5910
  • jim_thompson5910
so you can see that the slope of AC is -2/3 and the slope of MN is also -2/3 This means that AC and MN are parallel
anonymous
  • anonymous
Okay.. yeah then I find the length of?
jim_thompson5910
  • jim_thompson5910
yes you need the length of MN
anonymous
  • anonymous
I use distance formula for that?
jim_thompson5910
  • jim_thompson5910
yes
anonymous
  • anonymous
d = sqrt(-3-0)^2+(0-2)^2?
jim_thompson5910
  • jim_thompson5910
keep going
anonymous
  • anonymous
MN: d = sqrt(-3-0)^2+(0-2)^2 d = sqrt(-3)^2 + (-2)^2 d = sqrt(9) + (4) d = sqrt(13) d = 3.6
jim_thompson5910
  • jim_thompson5910
good
jim_thompson5910
  • jim_thompson5910
notice how AC is 7.2 units long (roughly) and MN is roughly 3.6 units long so MN is about half as long as AC (since 7.2/2 = 3.6)
anonymous
  • anonymous
did we satisfy the question? I think I got everything. This practice helped a lot.
jim_thompson5910
  • jim_thompson5910
yeah there's a lot to it, but I think we got everything
anonymous
  • anonymous
thanks.. I'm sorry this took so long
jim_thompson5910
  • jim_thompson5910
that's ok, you're welcome

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